8. Solve for x. -10x 8. 160 40° 45°

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A: ∫0π4tan2θsec2θa2+a2tan2θdθ =1a4∫tan2θsec2θ1+tan2θ2dθ =1a4∫tan2θsec2θsec2θ2dθ since 1+tan2θ=sec2θ…

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