8. The compound bar carries the loads of P and 2P as shown. Determine the maximum value of P that will satisfy the following requirements: allowable normal stress for steel is 35 ksi, allowable normal stress for aluminum is 18 ksi, and allowance for total deformation is 0.15 inch. Answer: P= 3.60 kips 2P Steel Aluminum A-06 in E-10 x 10 pi A-0.4 in E-29 x 10° pi

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter6: Stresses In Beams (advanced Topics)
Section: Chapter Questions
Problem 6.3.7P: The cross section of a beam made of thin strips of aluminum separated by a lightweight plastic is...
icon
Related questions
Question
7. The stress-strain diagram for polyester resin is shown in the figure. Both strut AB and column CD, made
from this material, support the rigid beam AC. Calculate the angle of tilt of the beam when it is subjected
to load P = 60 kN. The diameter of the strut is 50 mm and the diameter of the column is 80 mm.
Answer: 0 = 0.327²
Transcribed Image Text:7. The stress-strain diagram for polyester resin is shown in the figure. Both strut AB and column CD, made from this material, support the rigid beam AC. Calculate the angle of tilt of the beam when it is subjected to load P = 60 kN. The diameter of the strut is 50 mm and the diameter of the column is 80 mm. Answer: 0 = 0.327²
(MP)
100
95
60
50
compression
2m
tension
➡e (mm/mm)
0.01 0.02 0.03 0.04
8. The compound bar carries the loads of P and 2P as shown. Determine the maximum value of P that
will satisfy the following requirements: allowable normal stress for steel is 35 ksi, allowable normal stress
for aluminum is 18 ksi, and allowance for total deformation is 0.15 inch. Answer: P = 3.60 kips
2P
Aluminum
A=0.6 in
E-10 x 10 pi
Steel
A-0.4 in2
E-29 x 10 pi
Transcribed Image Text:(MP) 100 95 60 50 compression 2m tension ➡e (mm/mm) 0.01 0.02 0.03 0.04 8. The compound bar carries the loads of P and 2P as shown. Determine the maximum value of P that will satisfy the following requirements: allowable normal stress for steel is 35 ksi, allowable normal stress for aluminum is 18 ksi, and allowance for total deformation is 0.15 inch. Answer: P = 3.60 kips 2P Aluminum A=0.6 in E-10 x 10 pi Steel A-0.4 in2 E-29 x 10 pi
Expert Solution
steps

Step by step

Solved in 3 steps

Blurred answer
Knowledge Booster
Axial Load
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Mechanics of Materials (MindTap Course List)
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:
9781337093347
Author:
Barry J. Goodno, James M. Gere
Publisher:
Cengage Learning