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80.0 g of non-volatile maltose (molar mass = 342.34 g/mol) is added to 152 g of water (molar mass = 18.02 g/mol) at 35°C. The vapor pressure of water at 35°C is 42.2 Torr. Calculate the vapor pressure (in torr) of the resulting maltose solution. Link to Physical Constants Link to Periodic Table

80.0 g of non-volatile maltose (molar mass = 342.34 g/mol) is added to 152 g of water (molar mass = 18.02 g/mol) at 35°C. The vapor pressure of water at 35°C is 42.2 Torr. Calculate the vapor pressure (in torr) of the resulting maltose solution. Link to Physical Constants Link to Periodic Table

Introductory Chemistry For Today
Introductory Chemistry For Today
8th Edition
ISBN:9781285644561
Author:Seager
Publisher:Seager
Chapter7: Solutions And Colloids
Section: Chapter Questions
Problem 7.115E
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80.0 g of non-volatile maltose (molar mass = 342.34 g/mol) is added to 152 g of water (molar mass = 18.02 g/mol) at 35°C. The vapor pressure of water at 35°C is 42.2 Torr. Calculate the vapor pressure (in torr) of the resulting maltose solution. Link to Physical Constants Link to Periodic Table
Transcribed Image Text:80.0 g of non-volatile maltose (molar mass = 342.34 g/mol) is added to 152 g of water (molar mass = 18.02 g/mol) at 35°C. The vapor pressure of water at 35°C is 42.2 Torr. Calculate the vapor pressure (in torr) of the resulting maltose solution. Link to Physical Constants Link to Periodic Table
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