Please help Given the following test results in a course, answer the following questions 87855675349654745265789093157245876434- 5765748564986781a. Determine an appropriate interval length for this data.20Range: Highest Value Lowest Value =Possible interval lengths:Range =Range20Choose an Interval length:IntervalTallyFrequency0.5 tob. Sort the data into a frequency table.Use an appropriate interval length.

A range is the difference between the maximum value and minimum value of a dataset. It helps us…

Answered: 87 85 56 75 34 96 54 74 52 65 78 90 93…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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1. Create the frequency table of the data.
In a student survey, forty-one part-time students were asked how many courses they were taking this term. The (incomplete) results are shown below:Please round your answer to 4 decimal places for the Relative Frequency if possible.# of CoursesFrequencyRelative FrequencyCumulative Frequency1 0.2927122100.2439 319 41What percent of students take exactly one courses? %
Find the standard deviation of te average temperatures recorded over a five-day period last summer: 12,25,19,22,18. pls use table for computations
4) A transportation company owns 30 buses. The distance that each bus has traveled since it was purchased by the company is recorded. The cumulative frequency curve for these data is shown.a) Determine the value of the Rangeb) Estimate, from the curve, the quartilesc) Calculate the interquartile range (IQR)d) Estimate the number of buses that travel less than 5000 kme) More than how many km are traveled by 15% of the buses with the longest distancef) How many buses travel between 10,000 and 20,000 km?
Isle Royale, an island in Lake Superior, has provided an important study site of wolves and their prey. Of special interest is the study of the number of moose killed by wolves. In the period from 1958 to 1974, there were 296 moose deaths identified as wolf kills. The age distribution of the kills is as follows. Age of Moose in Years Number Killed by Wolves Calf (0.5 yr)1-56-1011-1516-20 1095271586 (a) For each age group, compute the probability that a moose in that age group is killed by a wolf. (Round your answers to four decimal places.) 0.5 1-5 6-10 11-15 16-20 (b) Consider all ages in a class equal to the class midpoint. Find the expected age of a moose killed by a wolf and the standard deviation of the ages. (Round your answers to two decimal places.) ? = ? =
The inner diameters of washers produced by a company can be measured to the nearest thousandth of an inch. If the class marks of a frequency distribution of these diameters are given in inches by 0.345,0.360, 0.375, 0.390, 0.405, 0.420, and 0.435, find a) the class size b) the class limits c) the class boundaries
In the manufacture of a certain scientific instrument great importance is attached to the life of a critical component. This component is obtained in bulk from two sources, A and B, and in a course of inspection, the lives of 1000 of the components from each source are determined. The following frequency tables are obtained:Source A Source BLife (hours) No. of components Life (hours) No. of components1000 – 1020 40 1030 – 1040 3391020 – 1040 96 1040 – 1050 1361040 – 1060 364 1050 – 1060 251060 – 1080 372 1060 – 1070 201080 – 1100 85 1070 – 1080 1301100 – 1120 43 1080 – 1090 350Examine the effectiveness of the measures of dispersion with which you are familiar for comparing the dispersion of the two distributions
Estimate the mean of the number of items purchased by randomly selected customers at a clothing store given in the following grouped frequency table. Round the final answer to two decimal places. Value Interval Frequency 1-3 12 4-6 9 7-9 7 10-12 7
A company collects data from 10,000 websites about how long it takes to load the site. The number of seconds it takes to fully load the website is summarized in the relative frequency table. seconds to load relative frequency 1.4–1.6 0.0003 1.6–1.8 0.0012 1.8–2.0 0.0053 2.0–2.2 0.0181 2.2–2.4 0.0442 2.4–2.6 0.0910 2.6–2.8 0.1555 2.8–3.0 0.1861 3.0–3.2 0.1938 3.2–3.4 0.1447 3.4–3.6 0.0923 3.6–3.8 0.0447 3.8–4.0 0.0166 4.0–4.2 0.0048 4.2–4.4 0.0012 4.4–4.6 0.0002 The relative frequency histogram summarizes the same data. Expand Image The mean time to load a website is 3 seconds and the standard deviation is 0.4 seconds. Would a normal distribution be a good model for this distribution? Explain your reasoning. What proportion of websites loaded within 1 standard deviation of the mean? What proportion of websites loaded within 2 standard deviations of the mean? What proportion of websites loaded within 1 standard deviation of 2.8 seconds?…
A manufacturer of computer stands made a batch of 40,000bases. 500 bases were taken to make a measurement of the width of thebase obtaining the following results.-Average: 20.10 cmStd Deviation: 1cmIf the customer's width specification of this base is: from 17.1 cm to22.5cm.For the batch of 40,000 bases,a) How many bases does the lot have below the maximum width?(including those that could be below the lower limit)b) What is the CPK of this process?
Isle Royale, an island in Lake Superior, has provided an important study site of wolves and their prey. Of special interest is the study of the number of moose killed by wolves. In the period from 1958 to 1974, there were 296 moose deaths identified as wolf kills. The age distribution of the kills is as follows. Age of Moose in Years Number Killed by Wolves Calf (0.5 yr)1-56-1011-1516-20 1084870682 (a) For each age group, compute the probability that a moose in that age group is killed by a wolf. (Round your answers to three decimal places.) 0.5 1-5 6-10 11-15 16-20 (b) Consider all ages in a class equal to the class midpoint. Find the expected age of a moose killed by a wolf and the standard deviation of the ages. (Round your answers to two decimal places.) μ = σ =
The manager of a fleet of automobiles is testing two brands of radial tires. She assigns one tire of each brand at random to the two rear wheels of eight cars and runs the cars until the tires wear out. The data are shown here (in km). Find a 99% CI on the difference in mean life. Which brand would you prefer, based on this calculation? Car Brand 1 Brand 2 1 36925 34318 2 45300 42280 3 36240 35500 4 32100 31950 5 37210 38015 6 48360 47800 7 38200 37810 8 33500 33215

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87 85 56 75 34 96 54 74 52 65 78 90 93 15 72 45 87 64 34 - 57 65 74 85 64 98 67 81 a. Determine an appropriate interval length for this data. Range: Highest Value Lowest Value = Range = 20 Possible interval lengths: Range =