+8x3 –7.8x4 = 24.1 7x1 –3.2x2 -8x3 -1.4x4 = -125 9.6x1 –8.8x2 +6x3 +0.3x4 = -23.2 2.7x1 –9.2x2 3.6x1 +0.7x2 –5.7x3 +8.6x4 = –-49.6 Coeficientes após escalonamento: x2 Eqı : -7.8 2.7 -9.2 8 24.1 Eq2 : Eq3 : Eq4 : Solução: -8,07835 -0,476100 x3 = 8,32058 X4 = 3,09169

+8x3 –7.8x4 = 24.1 7x1 –3.2x2 -8x3 -1.4x4 = -125 9.6x1 –8.8x2 +6x3 +0.3x4 = -23.2 2.7x1 –9.2x2 3.6x1 +0.7x2 –5.7x3 +8.6x4 = –-49.6 Coeficientes após escalonamento: x2 Eqı : -7.8 2.7 -9.2 8 24.1 Eq2 : Eq3 : Eq4 : Solução: -8,07835 -0,476100 x3 = 8,32058 X4 = 3,09169

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Question

Apply the Gauss Elimination Method without pivoting to solve the linear system below. You must not change lines. Fill in the first table below with the coefficients and independent terms of the system obtained after all the scaling steps. Note that the table is already partially filled. The second table must be filled with the system solution. Perform calculations with 4 decimal places and rounding. Use comma as separator for fractional values (Ex: 3.145 instead of 3.145).

+8x3 –7.8x4 = 24.1
721 -3.2а2 —843 — 1.424 3 —125
2.7x1 –9.2x2
9.6x1 -8.8x2 +6x3 +0.3x4 = -23.2
3.6x1 +0.7x2 –5.7x3 +8.6x4=-49.6
Coeficientes após escalonamento:
b
Eqı :
2.7
-9.2
8
-7.8
24.1
Eq2 :
Eqz :
Eq4 :
Solução:
-8,07835
X2 =
-0,476100
x3 =
8,32058
X4 =
3,09169

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