Chapter14: Principles Of Neutralization Titrations
Section: Chapter Questions
Problem 14.33QAP
Related questions
Question
Q 9 please
![Q1:Chose the correct answer from the following
1-The [HO] in a 0.050 M solution of Ba(OH), is:
(a) 1.0 x 10' M (b) 5.0 x 10 M (c) 10 x 10 M (d) 5.0 x 10" M
2-The pH of a 0.02 M solution of an unknown weak acid is 3.7. what is the pK, of this acid?
(a) 5.7 (b) 4.9
(d) 28
(c) 3.7
3-Which of the following solutions has the lowest pH at 25°C? (No calculations required.)
(a) 0.2 M sodium hydroxide (b) 0.2 M hypochlorous acid (c) 02 M ammonia (d) 0.2 M benzoic
acid (e) pure water
4-The pH of 0.15 M trimethylammonium chloride, (CH)NHCI, a salt, is 5.34. What is the percent
hydrolysis?
(a) 0,003% (b) 0.0068%
(c) 0.0094 %
(c) 0.022%
(d) 0.011 %
5-How many grams of NaF would have to be added to 2.00 L of 0.100 M HF to yield a solution with a pH
is 4.00% mw for NaF is 41.98 g/mol) Ka for HF 1.4 10
(a) 300 g
(b) 36 g
(c) 0.84 g
(d) 6.9 g
(c) 60. g
6-Calculate the pH of the solution resulting from the addition of 20.0 mL of 0.100 M NaOH to 30.0 ml. of
0.100 M HNO,
(a) 1.35
(b) 1.70
(c) 1.95
(d) 2.52
(c) 2.80
7-Consider the titrations of the pairs of aqueous acids and bases listed on the left. For which pair is the pH
at the equivalence point stated incorrectly?
Acid-Base Pair
tai
balls
(b) HNO-Ca(OH)
(e) 2.0 x 10¹ M
(HCIO, -NaOH
id) HCO NaOH
KHOA
pH at Equivalence Point
less than 7
(a) strong, strong
(b) weak, strong
(c) strong, weak
(d) weak, weak
(e) none of these
less than 7
8-The following titration curve is the kind of curve expected for the titration of a
base
pH 71
acid with a
mL added
9- A buffer system is set up with 3[HA] =[A]. If pK a -5.5, what is the pH of the buffer?
c. 5.3
a. 5.2
b. 3.5
d. 6.0
e. 7.5
10-If 25.00 ml of 0.1M NaOH solution is needed to reach the end point of 10 ml HNO₂. Then the concentration of
HNO, in ppm is: [M.wt. of HNO,-63 g/mol]
a. 9.45-10 ppm
b. 14.70×10 ppm
c. 7.30-10¹ ppm
d. 1.5750×10 ppm](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F46ef3182-b77b-4d5e-aa39-bd37ce4fcd02%2Fe5256afa-b35c-42c1-b8ff-f932969f67de%2Feyj3ozj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Q1:Chose the correct answer from the following
1-The [HO] in a 0.050 M solution of Ba(OH), is:
(a) 1.0 x 10' M (b) 5.0 x 10 M (c) 10 x 10 M (d) 5.0 x 10" M
2-The pH of a 0.02 M solution of an unknown weak acid is 3.7. what is the pK, of this acid?
(a) 5.7 (b) 4.9
(d) 28
(c) 3.7
3-Which of the following solutions has the lowest pH at 25°C? (No calculations required.)
(a) 0.2 M sodium hydroxide (b) 0.2 M hypochlorous acid (c) 02 M ammonia (d) 0.2 M benzoic
acid (e) pure water
4-The pH of 0.15 M trimethylammonium chloride, (CH)NHCI, a salt, is 5.34. What is the percent
hydrolysis?
(a) 0,003% (b) 0.0068%
(c) 0.0094 %
(c) 0.022%
(d) 0.011 %
5-How many grams of NaF would have to be added to 2.00 L of 0.100 M HF to yield a solution with a pH
is 4.00% mw for NaF is 41.98 g/mol) Ka for HF 1.4 10
(a) 300 g
(b) 36 g
(c) 0.84 g
(d) 6.9 g
(c) 60. g
6-Calculate the pH of the solution resulting from the addition of 20.0 mL of 0.100 M NaOH to 30.0 ml. of
0.100 M HNO,
(a) 1.35
(b) 1.70
(c) 1.95
(d) 2.52
(c) 2.80
7-Consider the titrations of the pairs of aqueous acids and bases listed on the left. For which pair is the pH
at the equivalence point stated incorrectly?
Acid-Base Pair
tai
balls
(b) HNO-Ca(OH)
(e) 2.0 x 10¹ M
(HCIO, -NaOH
id) HCO NaOH
KHOA
pH at Equivalence Point
less than 7
(a) strong, strong
(b) weak, strong
(c) strong, weak
(d) weak, weak
(e) none of these
less than 7
8-The following titration curve is the kind of curve expected for the titration of a
base
pH 71
acid with a
mL added
9- A buffer system is set up with 3[HA] =[A]. If pK a -5.5, what is the pH of the buffer?
c. 5.3
a. 5.2
b. 3.5
d. 6.0
e. 7.5
10-If 25.00 ml of 0.1M NaOH solution is needed to reach the end point of 10 ml HNO₂. Then the concentration of
HNO, in ppm is: [M.wt. of HNO,-63 g/mol]
a. 9.45-10 ppm
b. 14.70×10 ppm
c. 7.30-10¹ ppm
d. 1.5750×10 ppm
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps with 2 images
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Recommended textbooks for you