The vapor pressure of n-heptanol is 84.4 kPa at 443 K and its normal boiling point is It is 448K. Estimate the heat of evaporation of N-heptanol
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The vapor pressure of n-heptanol is 84.4 kPa at 443 K and its normal boiling point is It is 448K. Estimate the heat of evaporation of N-heptanol.
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- I am slightly confused on how to do this. I think I figured it out but I just want to compare data and take notes on what I have done incorrectly.In Active Example 3-29 you calculated that you would have to work six weeks to earn enough money to buy a 1082.49 television. You would be working five shifts of four hours each at 9.25/hr. But, alas, when you received your first pay check, you found that exactly 23 of your earnings had been withheld for social security, federal and state income taxes, and workers compensation insurance. Taking these into account, how many weeks will it take to earn the 1082.49?Chemistry Fraction no. Elution Vol. (mL) Abs (λ = 410) Fraction no. Elution Vol. (mL) Abs (λ = 410) 1 (PB pH 6.0) 1 0.0050 11 11 0.0041 2 2 0.0032 12 12 0.0060 3 3 0.0040 13 13 0.0064 4 4 0.0064 14 14 0.0063 5 5 0.0067 15 15 0.1109 6 6 0.0067 16 16 2.8902 7 7 0.0050 17 17 0.8500 8 (PB pH 8.0) 8 0.0049 18 18 0.2019 9 9 0.0052 19 19 0.0378 10 10 0.0050 20 20 0.0073 Use the data above to plot an elution profile, in which the absorbance is on Y-axis, and elution volume (volume = fraction number) is on X-axis. The elution profile must indicate at (1) which point the pH change occurred, (2) the fraction(s) which contain the highest myoglobin content, and (3) the maximum absorbance detected.
- Time(s) [X3] (mole/L) 0 0.600 200 0.458 400 0.362 600 0.281 800 0.204 1000 0.175 1200 0.134 1400 0.104 1600 0.083 1800 0.063 2000 0.047 plot ln[X3] vs time plot 1/[X3] vs timeA. B. and C. already solved (https://www.bartleby.com/questions-and-answers/chemistry-question/a89691d6-2162-4677-b0cc-dc84fcceda08). Please answer E, F and GCircle in pencil in the image on th eirght cide of the diagram is a "2"( Pb(NO3)2 ).a Table: (This is an example of what your data table should look like.) Pressure (kPa) Temperature (°C) Temperature (K) Constant, k(P / T or P•T) Ice water bath 91.58 2.4 275.55 Room temperature 96.54 21.1 294.25 Warm water 104.11 44.5 317.65 Boiling water 113.75 77.5 350.5 Calculations: One way to determine if a relationship is inverse or direct is to find a proportionality constant, k, from the data. If this relationship is direct, k = P/T. If it is inverse, k = P•T. Choose one of these formulas and calculate k for the pairs in your data table (divide or multiply the P and T values). Record the answers in the fourth column of the Data table. How constant were the values for k you obtained in Question 4? Good data may show some minor variation, but the values for k should be relatively constant. Comment on your calculated k values. Analysis Questions: What does temperature measure? Look at your graph. What type…
- 15.4a 3 please. 0.166 was incorrect.Chemistry (i) For T = 298K ΔG° = -8.314 x 298 x ln (2.83x10-3) = 14.524 KJ/mol (ii) For T = 308.15K ΔG° = -8.314 x 308.15 x ln (9.619x10-3) = 11.891 KJ/mol (iii) For T = 318.15K ΔG° = -8.314 x 318.15 x ln (3.14x10-2) = 9.147 KJ/mol (iv) For T = 328.15K ΔG° = -8.314 x 328.15 x ln (8.82x10-2) = 6.621 KJ/mol (v) For T = 338.15K ΔG° = -8.314 x 338.15 x ln (2.42x10-1) = 3.990 KJ/mol Based on the measured ΔG° values, is this equilibrium spontaneous at room temperature? Which factor, entropy, or enthalpy, has the greater impact on spontaneity in this case? Explain your answers.See image below. Can you please show me how to get to 0.00018 as the answer?
- Data obtained: Chips # of extractions Chips' weight (g) Fat weight (g) Regular 3 20.043 6.745 3 20.187 6.438 3 20.198 7.451 Low fat 3 19.456 3.982 3 20.072 4.547 3 20.192 4.589 Mass percent is a method of expressing the concentration of a substance in a mixture or element in a compound. It is calculated as the mass of the component divided by the total mass of the mixture and then multiplied by 100 to get the percent. The formula is: mass % of component= (mass of component / total mass) x 100% 1) Reproduce the following table, and use the data to determine the mass % of fat in the chips for each trial. 2) Show one example calculation. Chips Trial % by mass of fat Regular 1 2 3 Lowfat 1 2 3Parts G and H. I thought the answers were 56.21 and 115.21 but it says they're wrong.Hi! I am having difficulty finishing and finding out the rest of tables in excel. I am trying to find the Calcium Carbonate in an Eggshell. I have put up the excel sheet I have done with the given data already inputed, I just need to find out the rest. Thank you so much!