9. A 0.500 kg circular disc with a radius of 0.700 m is bound to rotate about its center. Three forces act on the object as depicted in the diagram below. Fj=5.00N, F=7.00 N and F3-5.00N. F3 is 0.400 m from the axis of rotation while the other two forces act tangentially. The moment of inertia the sheet about its center is I = mR2 35° F3 F1 F2 a. What is the net torque acting on the disc? b. If the object is initially at rest, what will its rotational kinetic energy be 7.00 s after the forces begin to be applied?

9. A 0.500 kg circular disc with a radius of 0.700 m is bound to rotate about its center. Three forces act on the object as depicted in the diagram below. Fj=5.00N, F=7.00 N and F3-5.00N. F3 is 0.400 m from the axis of rotation while the other two forces act tangentially. The moment of inertia the sheet about its center is I = mR2 35° F3 F1 F2 a. What is the net torque acting on the disc? b. If the object is initially at rest, what will its rotational kinetic energy be 7.00 s after the forces begin to be applied?

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter10: Rotational Motion And Angular Momentum

Section: Chapter Questions

Problem 2PE: Integrated Concepts An ultracentrifuge accelerates from rest to 100,000 rpm in 2.00 min. (a) What is...

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