9. Find the 90% confidence for the difference of the means in Exercise 1 of this section.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
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Author:Carter
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Chapter10: Statistics
Section10.4: Distributions Of Data
Problem 19PFA
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Problem 9 must be solved by exercise 1 of the session.
Exercises 9-3
the
For these exercises, perform each of these steps. Assume
that all variables are normally or approximately normally
distributed.
Use
Ch
a. State the hypotheses and identify the claim.
b. Find the critical value(s) or use the P-value method.
c. Compute the test value.
d. Make the decision.
e. Summarize the results.
N
6.
Use the traditional method of hypothesis testing unless
the P-value method is specified by your instructor. Assume
the variances are unequal.
1. Waterfall Heights Is there a significant difference
at a = 0.10 in the mean heights in feet of waterfalls in
Europe and the ones in Asia? The data are shown.
In Europe
Asia
487
1246
1385
614
722
964
470
1312
984
1137
320
830
900
345
820
350
722
1904
Source: World Almanac and Book of Facts.
2. Tax-Exempt Properties A tax collector wishes to see
if the mean values of the tax-exempt properties are dif-
ferent for two cities. The values of the tax-exempt prop-
erties for the two random samples are shown. The data
are given in millions of dollars. At a = 0.05, is there
enough evidence to support the tax collector's claim
that the means are different?
Transcribed Image Text:Exercises 9-3 the For these exercises, perform each of these steps. Assume that all variables are normally or approximately normally distributed. Use Ch a. State the hypotheses and identify the claim. b. Find the critical value(s) or use the P-value method. c. Compute the test value. d. Make the decision. e. Summarize the results. N 6. Use the traditional method of hypothesis testing unless the P-value method is specified by your instructor. Assume the variances are unequal. 1. Waterfall Heights Is there a significant difference at a = 0.10 in the mean heights in feet of waterfalls in Europe and the ones in Asia? The data are shown. In Europe Asia 487 1246 1385 614 722 964 470 1312 984 1137 320 830 900 345 820 350 722 1904 Source: World Almanac and Book of Facts. 2. Tax-Exempt Properties A tax collector wishes to see if the mean values of the tax-exempt properties are dif- ferent for two cities. The values of the tax-exempt prop- erties for the two random samples are shown. The data are given in millions of dollars. At a = 0.05, is there enough evidence to support the tax collector's claim that the means are different?
10.4
12.6
10.6
10.2
8.8
9.5
11.1
14.7
9.6
9.5
11.2
10.3
10.8
12.9
10.1
9.3
11.7
13.3
9.4
9.5
5
12.8
14.5
9.8
10.3
11.0
9
8. Teacher Salaries A researcher claims that the mean
of the salaries of elementary school teachers is greater
than the mean of the salaries of secondary school teach-
ers in a large school district. The mean of the salaries
of a random sample of 26 elementary school teachers is
$48,256, and the sample standard deviation is $3,912.40.
The mean of the salaries of a random sample of 24 sec-
ondary school teachers is $45,633. The sample standard
deviation is $5533. At a = 0.05, can it be concluded that
the mean of the salaries of the elementary school teachers
is greater than the mean of the salaries of the secondary
school teachers? Use the P-value method.
9. Find the 90% confidence for the difference of the means
in Exercise 1 of this section.
10. Find the 95% confidence interval for the difference of the
means in Exercise 6 of this section.
11. Hours Spent Watching Television According to
Nielsen Media Research, children (ages 2-11) spend
an average of 21 hours 30 minutes watching television
per week while teens (ages 12-17) spend an average
of 20 hours 40 minutes. Based on the sample statis-
tics shown, is there sufficient evidence to conclude a
9-19
Transcribed Image Text:10.4 12.6 10.6 10.2 8.8 9.5 11.1 14.7 9.6 9.5 11.2 10.3 10.8 12.9 10.1 9.3 11.7 13.3 9.4 9.5 5 12.8 14.5 9.8 10.3 11.0 9 8. Teacher Salaries A researcher claims that the mean of the salaries of elementary school teachers is greater than the mean of the salaries of secondary school teach- ers in a large school district. The mean of the salaries of a random sample of 26 elementary school teachers is $48,256, and the sample standard deviation is $3,912.40. The mean of the salaries of a random sample of 24 sec- ondary school teachers is $45,633. The sample standard deviation is $5533. At a = 0.05, can it be concluded that the mean of the salaries of the elementary school teachers is greater than the mean of the salaries of the secondary school teachers? Use the P-value method. 9. Find the 90% confidence for the difference of the means in Exercise 1 of this section. 10. Find the 95% confidence interval for the difference of the means in Exercise 6 of this section. 11. Hours Spent Watching Television According to Nielsen Media Research, children (ages 2-11) spend an average of 21 hours 30 minutes watching television per week while teens (ages 12-17) spend an average of 20 hours 40 minutes. Based on the sample statis- tics shown, is there sufficient evidence to conclude a 9-19
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