In Exercises 8–16, give a geometric description of the set of points in space whose coordinates satisfy the given pairs of equations. 9. х2 + у2 + 2? %3D 1, х%3D010. х2 + у2 + 2? %3D 25, у %3D —-411. х? + у? + (2 + 3)? %3D 25, 2z%3D 012. х2 + (у — 1)? + 2? 3D 4, у%3D 013. х? + у2 %3 4, Z%3Dу14. х2 + у? + z? %3D 4, у%3Dх15. у %3D х?,16. z = y?, x = 1z = 0

Answered: Image /qna-images/answer/003edaa6-686d-43ed-bdb0-3101291514ee.jpg

9. х2 + у2 + 2? %3D 1, х%3D0 10. х2 + у2 + 2? %3D 25, у %3D —-4 11. х? + у? + (2 + 3)? %3D 25, 2z%3D 0 12. х2 + (у — 1)? + 2? 3D 4, у%3D 0 13. х? + у2 %3 4, Z%3Dу 14. х2 + у? + z? %3D 4, у%3Dх 15. у %3D х?, 16. z = y?, x = 1 z = 0

9. х2 + у2 + 2? %3D 1, х%3D0 10. х2 + у2 + 2? %3D 25, у %3D —-4 11. х? + у? + (2 + 3)? %3D 25, 2z%3D 0 12. х2 + (у — 1)? + 2? 3D 4, у%3D 0 13. х? + у2 %3 4, Z%3Dу 14. х2 + у? + z? %3D 4, у%3Dх 15. у %3D х?, 16. z = y?, x = 1 z = 0

College Algebra (MindTap Course List)

12th Edition

ISBN:9781305652231

Author:R. David Gustafson, Jeff Hughes

Publisher:R. David Gustafson, Jeff Hughes

Chapter6: Linear Systems

Section6.2: Guassian Elimination And Matrix Methods

Problem 84E: Explain the differences between Gaussian elimination and Gauss-Jordan elimination.

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Concept explainers

Linear Algebra

In mathematics, problems can be solved by the arithmetic operators like addition, subtraction, multiplication, and division. In algebra, we represent the numbers by any letter called a variable. If these variables are of degree 1, then it is studied under linear algebra. The first-degree equations involving algebraic expressions are called linear equations. That is, if you represent it by drawing a graph you will get a straight line.

Question

In Exercises 8–16, give a geometric description of the set of points in space whose coordinates satisfy the given pairs of equations.

9. х2 + у2 + 2? %3D 1, х%3D0
10. х2 + у2 + 2? %3D 25, у %3D —-4
11. х? + у? + (2 + 3)? %3D 25, 2z%3D 0
12. х2 + (у — 1)? + 2? 3D 4, у%3D 0
13. х? + у2 %3 4, Z%3Dу
14. х2 + у? + z? %3D 4, у%3Dх
15. у %3D х?,
16. z = y?, x = 1
z = 0

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