9o. Write a recursive function printRev ( int a[ ], int s, int e) that receives an integer array a [ ], a start index s, and an end index e. The function should print the array elements in reverse order. void printRev ( int a[ ], int s, int e); Trace your function given the following array and function call. Draw your steps. int a[ ] = {4, 2, 3, 5};and printRev(a, 0, 3); language c++ .
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9o.
Write a recursive function printRev ( int a[ ], int s, int e) that receives an integer array a [ ], a start index s, and an end index e. The function should print the array elements in reverse order.
void printRev ( int a[ ], int s, int e);
Trace your function given the following array and function call. Draw your steps.
int a[ ] = {4, 2, 3, 5};and
printRev(a, 0, 3);
language c++ .
Step by step
Solved in 2 steps
- Write a Python function def isSubArray(A,B) which takes two arrays and returns True if the first array is a (contiguous) subarray of the second array, otherwise it returns False. You may solve this problem using recursion or iteration or a mixture of recursion and iteration. For an array to be a subarray of another, it must occur entirely within the other one without other elements in between. For example: [31,7,25] is a subarray of [10,20,26,31,7,25,40,9] [26,31,25,40] is not a subarray of [10,20,26,31,7,25,40,9] A good way of solving this problem is to make use of an auxiliary function that takes two arrays and returns True if the contents of the first array occur at the front of the second array, otherwise it returns False. Then, A is a subarray of B if it occurs at the front of B, or at the front of B[1:], or at the front of B[2:], etc. Note you should not use A == B for arrays.Implement a recursive C++ function which takes an integer array (A) and the starting (start) and ending(end) indices of that array, and returns the sum of all elements present in that array. The prototype ofyour function should be:int findSum (int* A, int start, int end)Q#2 Write a recursive function zeroCount ( int a[ ], int s, int e) that receives an array of integers a [], a start index s, and an end index e. The function should return the number of zeros in that array between s and e. int zeroCount ( int a[ ], int s, int e); Trace your function given the following array and function call. Draw your steps. int a[ ] = {1, 0, 0, 5}; int zeros = zeroCount(a, 0, 3); language c++
- Write a recursive function named reverseWithinBounds that has an argument that is an array of characters and two arguments that are bounds on array indices. The function should reverse the order of those entries in the array whose indices are between the two bounds (including the bounds). For example, if the array is: a[0] == 'A' a[1] == 'B' a[2] == 'C' a[3] == 'D' a[4] == 'E' and the bounds are 1 and 4, then after the function is run the array elements should be: a[0] == 'A' a[1] == 'E' a[2] == 'D' a[3] == 'C' a[4] == 'B' Embed the function in a program and test it. After you have fully debugged this function, define another function named reverseCstring that takes a single argument that is a C string and modifies the argument so that it is reversed. This function will include a call to the recursive definition you did for the first part of this project, and need not be recursive. Embed this second function in a program and test it.Write a recursive function named reverseWithinBounds that has an argument that is an array of characters and two arguments that are bounds on array indices. The function should reverse the order of those entries in the array whose indices are between the two bounds (including the bounds). For example, if the array is: a[0] == 'A' a[1] == 'B' a[2] == 'C' a[3] == 'D' a[4] == 'E' and the bounds are 1 and 4, then after the function is run the array elements should be: a[0] == 'A' a[1] == 'E' a[2] == 'D' a[3] == 'C' a[4] == 'B' Embed the function in a program and test it. After you have fully debugged this function, define another function named reverseCstring that takes a single argument that is a C string and modifies the argument so that it is reversed. This function will include a call to the recursive definition you did for the first part of this project, and need not be recursive. Embed this second function in a program and test it. Turn in only this final result (with output,…Write a recursive function named reverseWithinBounds that has an argument that is an array of characters and two arguments that are bounds on array indices. The function should reverse the order of those entries in the array whose indices are between the two bounds (including the bounds). For example, if the array is: a[0] == 'A' a[1] == 'B' a[2] == 'C' a[3] == 'D' a[4] == 'E' and the bounds are 1 and 4, then after the function is run the array elements should be: a[0] == 'A' a[1] == 'E' a[2] == 'D' a[3] == 'C' a[4] == 'B'
- Implement a recursive C++ function which takes an array of integers (arr) and the starting (start) andending (end) indices of a portion (part) of this array, and returns the index of thelargest element present in that portion of array arr. The prototype of your function should be:int findLargest (int* arr, int start, int end) For example, the function call findLargest(arr,3,8)should determine and return the index of the largest element present in the array arr between the indices 3and 8 (both inclusive)Using recursion, write a Python function def before(k,A) which takes an integer k and an array A of integers as inputs and returns a new array consisting of all the integers in A which come before the last occurrence of k in A, in the same order they are in A. For example, if A is [1,2,3,6,7,2,3,4] then before(3,A) will return [1,2,3,6,7,2]. If k does not occur in A, the function should return None.Write a recursive function that, given a sequence of comparable values, returns the count of elements where the current element is less than the following ( next ) element in the given sequence. See the examples given below. def count_ordered ( seq ) : """ Input : A sequence of comparable elements Output : The number of elements that are less than the following element in the sequence Example : >>> count_ordered ( [ 1 , 2 , 3 , 4 , 5 , 6 ] ) 5 >>> count_ordered ( ( 1 , 12, 7.3 , -2,4 ) ) 2 >>> count_ordered ( 'Python' ) 2 >>> count_ordered ( [ 6 ] ) 0 >>> count_ordered ( [ ] ) 0 """ In the first example above , count_ordered ( [ 1,2,3,4,5,6 ] )the returned answer is 5 because for all the first 5 numbers the current number is less than the next number. In the second example above, count_ordered ( ( 1,12,7.3 , -2,4 ) )the…
- Below,enter code to complete implementation of a recursive function sum_all_integers(), which takes an input n and adds all intergers preceding it, up to n: add_all_integers(n):Using recursion, write a Python function def countOdds(A) which which takes an array of integers A as input and returns the number of elements in the array that are odd. For example, if A is [1,2,5,3,6,5,3,5,5,4] the the function should return 7. If A is empty then it should return 3. Hint: To check if n is odd it suffices to check if dividing it by 2 gives remainder 1 (in Python, this remainder is calculated by n%2).Language: C Write a program to reverse an array using recursion. a) Declare an array of N integers. Use the preprocessor #define directive for the size of the array. Fill it with pseudorandom numbers. b) Define the recursive procedure, that reverses the array by swapping the last with the first element, and then recursively swapping the remaining subarray. To this end, define the function void reverseArray(int *inputArray, int leftIndex, int rightIndex). The function should stop the recursion, whenever leftIndex >= rightIndex. c) Print your original, and the reversed array. Test your results for both even, and for odd N.