9| Encrypt the message MATH using the RSA system with prime numbers p = 43 and q = 59 and n = 5. A BCDEFGHIJKL M Nq P QR S TU y w x Y Z 이이00 이 이 이 0 0 이 1| 1| 1| 1| 1| 1| 1| 1| 1| 1| 2| 2| 2| 2| 2| 2 0 1 2| 3 4 5 6 7 8| 9| 0| 1 2| 3| 4 5 6 7 8 9| 0| 1 2| 3 4 5
Q: Encrypt : QuiZ Cresar cypher is OVER using the with $ (p) = p+18 (mod 2b Let AこO, B=, Z=25
A: Given plain text is QUIZ IS OVER Also given f(p) = p+18(mod 26) So, key is 18
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cryptography
Encrypt the message MATH using the RSA system with prime numbers p = 43 and q = 59 and n = 5
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- f g а C h m O e 1 b d n j P k4. For each of the following, match the values on the left to those on the right. g. CAFE 16 h.42 1.145 j.101110102 k. 110101112 1. CODE 16 1.215 2.11001010111111102 3. BA16 4.111102 + 11002 5.100100012 6.49370Q#2: In the following equation, determine: (243. n ) = ( 1110011.0100 )BCD i. The unknown base x. 11. The value of n in the fraction part.
- The 2’s compliment of the binary number (1101100)2 is: Select one: a. None of the given options b. (0010100)2 c. (1101100)2 d. (0010011)2IN ASSEMBLY LANGUAGE BUT MAKE IT EASIER AND EXACTLY THE SAME OUTPUT PLEASE if you want to encrypt, typeE:", "if you want to decrypt, typeD:Eenter the encryption key(a single digit fron 1 to 9): 1 input a message of no nore than 20 characters. when done, press 〈enter : abc encryption message: bcd if you want to encrypt, typeE:," "if you want to decrypt, type D: E enter the encryption key(a single digit fron 1 to 9): 2 encryption message: cde if you want to encrypt, typeE:", "if you want to decrypt, type D: -n Cder e gr A-80 Cmp e OLLON f de YmLnd d dnd e de POLLON ding de a le de FOLLON REEd e
- E x e r c i s e • 1 : Apply frequency test to verify the randomness of the output of the following text: 1. The following plaintext: In cryptography, a transposition cipher (also known as a permutation cipher) is a method of encryption which scrambles the positions of characters (transposition) without changing the characters themselves. Transposition ciphers reorder units of plaintext (typically characters or groups of characters) according to a regular system to produce a ciphertext which is a permutation of the plaintext. They differ from substitution ciphers, which do not change the position of units of plaintext but instead change the units themselves. Despite the difference between transposition and substitution operations, they are often combined, as in historical ciphers like the ADFGVX cipher or complex high-quality encryption methods like the modern Advanced Encryption Standard (AES). laintexts can be rearranged into a ciphertext using a key, scrambling the order of…2. , A string encoded with H(12,8) SECDED is received as 0x500 Is it in error? Which bits are in error? extract the original message, show your work Bit position 1 2 3 4 5 6 7 8 9 10 11 12 Encoded date bits p1 p2 d1 p4 d2 d3 d4 p8 d5d6d7d8 X X X X X Parity X X X X X X bit coverate X X X X X X X X received Ox500 4 5 6 9 10 11 12 d1 p4 d2 d3 d5 d6 d7 d8 1 0 0 0 0 0 0 value should be 0 1 1 0 bit in error = bit position received message corrected original message p1 X p2 p4 p8 1 2 p1 p2 0 1 0 p1 p2 p4 p8 X X 7 8 d4 p8 0 0 in error? hex value 0x500A friend gives you the following random number generator:out: random integer rconstant: modulus m; starting value X0local: previously generated random number x (initially x = X0)1: if x mod 2 = 0 then2: r ← (x + 3) · 53: else if x mod 3 = 0 then4: r ← (x + 5) 314159265 Bitwise exclusive-or.5: else if x mod 5 = 0 then6: r ← x27: else8: r ← x + 79: end if10: r ← r mod m; x ← r11: return rHow can you verify how well (or poorly) it works?
- A binary code uses ten bits to represent each of the ten decimal digits. Each digit is assigned a codeof nine 0’s and a 1. The code for digit 6, for example, is 0001000000. Determine the binary code forthe remaining decimal digits.Q6/ If XY'+Y=X+Y the correct answer O None of them O X'Y'Z+XY=Z+XY XYZ+X'+Y=Z+XY OXY'Z'+Y+Z=X+Y+Z O X'YZ+Y'=XZ+Y' O XYZ'+Y'Z=X+YZ' ChoseGiven three floating-point numbers x, y, and z, output x to the power of z, x to the power of (y to the power of z), the absolute value of y, and the square root of (xy to the power of z). Ex: If the input is: 3.6 4.5 2.0 the output is: 12.96 1.841304610218211E11 4.5 16.2 Produce in Java language!