(a) 0 kN to 28 KN

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter11: Columns
Section: Chapter Questions
Problem 11.3.21P: A pinned-end strut of aluminum (E = 10,400 ksi) with a length L = 6 ft is constructed of circular...
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I am only interested in part 6-27(a). I see that Bartleby has answered this question before but I have a question regarding the yielding factor of safety. Why is the yielding factor of safety calculated as ( n=Sy/sigma_max), but not as ( n=Sy/Kf*sigma_max)? Since there is stress concentration factor.

(6-27 Using the Goodman criterion for infinite life, repeat Problem 6-25 for each of the
following loading conditions:
(a) 0 kN to 28 kN
(b) 12 kN to 28 kN
(c) 28 kN to 12 kN
6-25 The cold-drawn AISI 1040 steel bar shown in the figure is subjected to a completely
reversed axial load fluctuating between 28 kN in compression to 28 kN in tension.
Estimate the fatigue factor of safety based on achieving infinite life and the yielding.
factor of safety. If infinite life is not predicted, estimate the number of cycles to failure.
em 6-25
25 mm
10 mm
6-mm D.
Transcribed Image Text:(6-27 Using the Goodman criterion for infinite life, repeat Problem 6-25 for each of the following loading conditions: (a) 0 kN to 28 kN (b) 12 kN to 28 kN (c) 28 kN to 12 kN 6-25 The cold-drawn AISI 1040 steel bar shown in the figure is subjected to a completely reversed axial load fluctuating between 28 kN in compression to 28 kN in tension. Estimate the fatigue factor of safety based on achieving infinite life and the yielding. factor of safety. If infinite life is not predicted, estimate the number of cycles to failure. em 6-25 25 mm 10 mm 6-mm D.
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Just want to clarifiy, when a ductile material is subjected to a static load there will be no effects of concentration factor due to localized yielding. Is this because under the static load, when the stress near the discontinuity reaches the yield point, local plastic deformation takes place and increases the yield strength?

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Sorry I meant to say: Why is the yielding factor of safety calculated as ( n=Sy/sigma_max), but not as ( n=Sy/Kt*sigma_max)? Since there is stress concentration factor.

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