A 0.5130 g aspirin tablet which was dissolved in 95% ethanol required NaOH for neutralization. In the experiment, 42.78mL of 0.10000 M NaOH was added and the solution was heated to hydrolyze the acetylsalicylic acid. After the reaction mixture was cooled, the excess base was back-titrated with 14.29mL of 0.1056 M HCl. What % w/w of the tablet is acetylsalicylic acid (MM = 180.16 g/mol)? ---> CH3COOC6H4COOH (s) + 2 NaOH (aq) - (aq) + H2O (I) NaOH (aq) + HCI (aq) ---> NaCl (aq) + H₂O B 97.75% 13.07% 50.96% 48.62% CH3COONa (aq) + HỌC6H4COONa

Fundamentals Of Analytical Chemistry
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Chapter13: Titrations In Analytical Chemistry
Section: Chapter Questions
Problem 13.28QAP
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A 0.5130 g aspirin tablet which was dissolved in 95% ethanol required NaOH
for neutralization. In the experiment, 42.78mL of 0.10000 M NaOH was
added and the solution was heated to hydrolyze the acetylsalicylic acid.
After the reaction mixture was cooled, the excess base was back-titrated
with 14.29mL of 0.1056 M HCI. What % w/w of the tablet is acetylsalicylic
acid (MM 180.16 g/mol)?
CH3COOC6H4COOH (s) + 2 NaOH (aq) ---> CH3COONa (aq) + HOC6H4COONa
(aq) + H2O (I)
NaOH (aq) + HCI (aq) -
--->
A 97.75%
B
13.07%
50.96%
48.62%
NaCl (aq) + H₂O
Transcribed Image Text:A 0.5130 g aspirin tablet which was dissolved in 95% ethanol required NaOH for neutralization. In the experiment, 42.78mL of 0.10000 M NaOH was added and the solution was heated to hydrolyze the acetylsalicylic acid. After the reaction mixture was cooled, the excess base was back-titrated with 14.29mL of 0.1056 M HCI. What % w/w of the tablet is acetylsalicylic acid (MM 180.16 g/mol)? CH3COOC6H4COOH (s) + 2 NaOH (aq) ---> CH3COONa (aq) + HOC6H4COONa (aq) + H2O (I) NaOH (aq) + HCI (aq) - ---> A 97.75% B 13.07% 50.96% 48.62% NaCl (aq) + H₂O
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