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A 0.5-m length of wire is held in an east–to-west directionand moves horizontally to the north with a speed of 2.0 m/s. In this region, the Earth’s magnetic field is of magnitude 60.0 μT and is directednorthward and 53.1 degrees below the horizontal. (a) Calculate the magnitude of the induced emf between the ends of the wire and (b) determine which end is positive.

Question

A 0.5-m length of wire is held in an east–to-west direction
and moves horizontally to the north with a speed of 2.0 m/s. In this region, the Earth’s magnetic field is of magnitude 60.0 μT and is directed
northward and 53.1 degrees below the horizontal. (a) Calculate the magnitude of the induced emf between the ends of the wire and (b) determine which end is positive.

check_circleAnswer
Step 1

Write the expression f...

= Bsin elv
8
1T
(sin 53.1°)(0.5m)(2.0m/s)
60.0 106 T
X
-4.798 x 105 v
(a)The magnitude of induced emfbetween the ends of the wire is
4.798 x 10
V
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= Bsin elv 8 1T (sin 53.1°)(0.5m)(2.0m/s) 60.0 106 T X -4.798 x 105 v (a)The magnitude of induced emfbetween the ends of the wire is 4.798 x 10 V

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