A 1.00 liter flask contained 0.775 mol SO3 at 900 K which decomposed according to the reaction 2 SO3(g) = 2 SO2(g) + O2(g). At equilibrium the amount of SO2 was measured to be 0.133 mol, what is the value of K.
A 1.00 liter flask contained 0.775 mol SO3 at 900 K which decomposed according to the reaction 2 SO3(g) = 2 SO2(g) + O2(g). At equilibrium the amount of SO2 was measured to be 0.133 mol, what is the value of K.
Chemistry by OpenStax (2015-05-04)
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ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter16: Thermodynamics
Section: Chapter Questions
Problem 50E: Consider the decomposition of CaCO3(s) into CaO(s) and Co2(g). What is the equilibrium partial...
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Question
![A 1.00 liter flask contained 0.775 mol SO3 at
900 K which decomposed according to the
reaction
2 SO3(g) = 2 SO2(g) + O2(g).
At equilibrium the amount of SO2 was
measured to be 0.133 mol, what is the value
of Kc
ANS:2.85E-3
Show work please](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F767f35c7-c753-40b3-b549-e6587bc3199f%2F257e9732-b3b6-4aab-9482-787a1f4295ee%2Fiefrgsk_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A 1.00 liter flask contained 0.775 mol SO3 at
900 K which decomposed according to the
reaction
2 SO3(g) = 2 SO2(g) + O2(g).
At equilibrium the amount of SO2 was
measured to be 0.133 mol, what is the value
of Kc
ANS:2.85E-3
Show work please
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