A 1.850 kg block of wood rests on a steel desk. The coefficient of static friction between the block and the desk is u, = 0.555 and the coefficient of kinetic friction is = 0.305. At time t 0, a force F 6.19 N is applied horizontally to the block. State the force of friction applied to the block by the table at times t = 0 andt > 0.

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Chapter1: Units, Trigonometry. And Vectors
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A 1.850 kg block of wood rests on a steel desk. The coefficient of static
friction between the block and the desk is us
= 0.555 and the coefficient of
kinetic friction is
Hk
0.305. At time t =
0, a force F
6.19 N is applied
horizontally to the block. State the force of friction applied to the block by
Us.k
the table at times t = 0 and t > 0.
t = 0
6.19
N
1 > 0
6.19
Consider the same situation, but this time the external force F is 12.5 N. Again, state the force of friction acting on the block at
times t =
0 and t > 0.
5.53
t > 0
5.53
t = 0
N
Incorrect
Transcribed Image Text:A 1.850 kg block of wood rests on a steel desk. The coefficient of static friction between the block and the desk is us = 0.555 and the coefficient of kinetic friction is Hk 0.305. At time t = 0, a force F 6.19 N is applied horizontally to the block. State the force of friction applied to the block by Us.k the table at times t = 0 and t > 0. t = 0 6.19 N 1 > 0 6.19 Consider the same situation, but this time the external force F is 12.5 N. Again, state the force of friction acting on the block at times t = 0 and t > 0. 5.53 t > 0 5.53 t = 0 N Incorrect
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