A 100 mL solution of 0.1 M amino acid (AA) at pH 1.0 was titrated with 1.0 M NaOH solution. The pH was monitored, and the results were plotted on a graph, as shown below. The key points in the titration are I to VII. designated 12 10 -9.7 817 pH 6 4 2 3.9. 2.0 0 1 0.5 1 IV V VI 1.5 2 2.5 Equivalents of OH 3 VII
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- You are supplied with the following: NaCl (Mr = 58.443 g/mol) 2.5 M Tris-Cl, pH 8 oplossing / solution (1 Litre) EDTA, sodium salt (Mr = 380.2 g/mol) 10 % Sodium dodecyl sulfate solution Proteinase K solution (50 mg dissolved in 1 ml ddH2O)You need a digestion buffer consisting of the following: 15 mM NaCl 75 mM Tris-Cl, pH 8 16 mM EDTA, pH 8 0.8 % Sodium dodecyl sulfate 0.75 mg/ml proteinase KCalculate: How will you prepare 500 ml of the digestion buffer?TE buffer consists of 10 mM of Tris-Cl, pH 7.6 and 1mM of EDTA, pH 8.0. You need to prepare 3L of TE buffer and you have the following stock solutions: 500 mM Tris-Cl and 1 M EDTA. How will you prepare the 3L of TE? Write work clearlyThe pH of a 0.0082 M solution of HNO₃ is
- What is the molarity of a NaOH solution if 48.0 mLneutralizes 35.0 mL of 0.144 M H2SO4?The prescriber ordered oxacillin 500mg IM q6h. The instructions on the 2g vial state to reconstitute the powder with "11.5mL of sterile water for injection, yielding 250mg/1.5mL" Whatis the strength of the reconstituted solution? How many milliliters would you administer?NaCl (Mr = 58.443 g/mol) 2.5 M Tris-Cl, pH 8 oplossing / solution (1 Litre) EDTA, sodium salt (Mr = 380.2 g/mol) 10 % Sodium dodecyl sulfate solution Proteinase K solution (50 mg dissolved in 1 ml ddH2O) You need a digestion buffer consisting of the following: 15 mM NaCl 75 mM Tris-Cl, pH 8 16 mM EDTA, pH 8 0.8 % Sodium dodecyl sulfate 0.75 mg/ml proteinase K Calculate: How will you prepare 500 ml of the digestion buffer? Show all your steps and calculations and remember to explain how exactly you will make it up.
- Describe the preparation of the following solutions include all mathematic calculations and equipment of the laboratory needed A.500 mm of a solution of KNO 1.50 M B. 150 g of a solution 5.0% of NaC2H3O2 C. 500 mm of a solution of NaOH 0.50 M from a solution of NaOH 6.0 M3. a) An aqueous solution is 3.50% by mass potassium bromide, KBr, and has a density of 1.02 g/mL. The molality of potassium bromide in the solution is _________m. b)An aqueous solution of magnesium nitrate has a concentration of 0.474 molal. The percent by mass of magnesium nitrate in the solution is _________%. c)An aqueous solution of cobalt(II) bromide has a concentration of 0.153 molal. The percent by mass of cobalt(II) bromide in the solution is _________%.The iodine contained in every one mL of the 0.010 M iodine solution in the buret will react with 1.76 mg of vitamin C. (In other words, every mL of iodine solution needed for the titration indicates the presence of 1.76 mg of vitamin C in the juice sample.) If your titration used 7.11 mL of iodine solution, what mass of vitamin C is in your fruit juice sample (in milligrams, mg)? Include the unit and two decimal places in your answer.