Another exam question in biological chemistery from last year. I have an exam in biological chemistery this month, so I try to be prepared. I'm trying to figure out how to calculate WITHOUT using computer (its not allowed during exam). I will appreciate details when explaining this exercise, so I can understand it. Thank you The kinetics of an enzyme have been investigated experimentally. Some of the results aregiven in the figure below in the form of a Lineweaver-Burk plot (sometimes called a doublereciprocal plot). In this experiment, the enzyme concentration was 11.5 nM (i.e. 1.15 x 10-8M).1/V (s/mM)25002000150010005000ODDO01002001/[S] mM-1300400 A: State the Lineweaver Burke equation.B: Calculate the kinetic parameters Vmax and KM from the figure.C: Estimate the turnover number of the enzyme.

Parameters such as Km and Vmax are used for comparing enzyme activities. If we know the initial rate…

Answered: A: State the Lineweaver Burke equation.…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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Another exam question in biological chemistery from last year. I have an exam in biological chemistery this month, so I try to be prepared. I'm trying to figure out how to calculate WITHOUT using computer (its not allowed during exam).

I will appreciate details when explaining this exercise, so I can understand it. Thank you

The kinetics of an enzyme have been investigated experimentally. Some of the results are
given in the figure below in the form of a Lineweaver-Burk plot (sometimes called a double
reciprocal plot). In this experiment, the enzyme concentration was 11.5 nM (i.e. 1.15 x 10-8
M).
1/V (s/mM)
2500
2000
1500
1000
500
0
ODDO
0
100
200
1/[S] mM-1
300
400

A: State the Lineweaver Burke equation.
B: Calculate the kinetic parameters Vmax and KM from the figure.
C: Estimate the turnover number of the enzyme.

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Thank you for helping me. I have to questions. In solution B, if we choose two other points on the graph for calculating the slope, wouldnt the values for Km/Vmax be different than 6.1? Why did you choose exactly those points on the graph?

Another thing, I understand the method you used to get to Km/Vmax= slope, but how did you then get the value for Vmax to be 10 mM/s??

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