A 100.0 ml. solution of 0.0200 M Fe³* in I M HCIO, is titrated with 0.100 M Cu*, resulting in the formation of Fe2* and Cu²*. A Pt indicator electrode and a saturated Ag|AgCl electrode are used to monitor the titration. Write the balanced titration reaction. titration reaction: Complete the two half-reactions that occur at the Pt indicator electrode. Write the half-reactions as reductions. half-reaction: Cu +e = E = 0.161 V half-reaction: Fe +e E = 0.767 V

Principles of Instrumental Analysis
7th Edition
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Chapter23: Potentiometry
Section: Chapter Questions
Problem 23.14QAP
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A 100.0 ml. solution of 0.0200 M Fe* in I M HCIO, is titrated with 0.100 M Cu*, resulting in the formation of Fe* and
Cu*. A Pt indicator electrode and a saturated Ag|AgCl electrode are used to monitor the titration.
Write the balanced titration reaction.
titration reaction:
Complete the two half-reactions that occur at the Pt indicator electrode. Write the half-reactions as reductions.
half-reaction:
Cu + e
E = 0.161 V
half-reaction:
Fe +e =
E = 0.767 V
Transcribed Image Text:A 100.0 ml. solution of 0.0200 M Fe* in I M HCIO, is titrated with 0.100 M Cu*, resulting in the formation of Fe* and Cu*. A Pt indicator electrode and a saturated Ag|AgCl electrode are used to monitor the titration. Write the balanced titration reaction. titration reaction: Complete the two half-reactions that occur at the Pt indicator electrode. Write the half-reactions as reductions. half-reaction: Cu + e E = 0.161 V half-reaction: Fe +e = E = 0.767 V
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