A 120 kN 15 kN/m HIIIIc Į EIIII PAWANNACRO CONGO G B F D Hinge Hinge -8 m-5 m+5 m-5 m+5 m - 8 m - 10 kN/m
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Draw the shear and bending moment diagrams for the beam shown.
a. Determine the maximum shear.
b. Determine the maximum moment.
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- I cannot understand these For point of contraflexural, 40090300=200×x90300 x=2 m θA=0 (fixed support) θDA=θD-θA=θD=Area of MEI Dia between A and D = 19030012×600×3+600×4+12×300×3-12×200×2 =355090300 θD=0.03931 radianθD= 2.252° Deflection at point D ∆D=31-CosθD ∆D=2.3176×10-3 mm Deflection at point D is 2.3176×10-3 mmx = 137y = 37a = 6b = 8c = 1sorry,what are these: Step 3 Slope deflection equation In section AB MAB= MFAB+22EIL2θA+θB-3δLMAB= -12.5+4EI5θB MBA= 12.5+4EI52θB In section BC MBC= 0+2EI52θB+θC MCB= 2EI5θB+2θC In section CD MCD= -16.67+4EI52θC MDC= 16.67+4EI5θC arrow_forward Step 4 Equilibrium equations Equilibrium equations MBA+MBC= 0 -(i)MCB+MCD= 0 -(ii) Now, From i12.5+8EIθB5+4EIθB5+2EIθC5= 0EIθB125+EIθC25 = -12.5 -(iii) From ii2EIθB5+4EIθC5+-16.67+8EIθC5=02EIθB5+EIθC125= 16.67 iv Solving equations (iii) and (iv), we get EIθB= -6.548EIθC = 8.037
- water is flowing through a 35cm diameter welded steel pipe (f=0.014) of length 2300m that drains a reservoir under a head of 50m. the pipe has a thickness of 9mm. if the valve at the end of the pipe is closed in 9s. approximately what water-hammer a. 1.667MPa b. 1.567 MPa c. 1.467 MPa d. 1.367MpaDerive S = S0 + V0t + (1/2)at2a=2 b=5 3xb=15x mm 12xb=60x mm 10xa kN = 20x kN ((3xb)-0,00735)) = (15x- 0,00735) mm
- a.) Q=0.56m/s. V=1.16m/s b.)D=420mm. q=5.5x10^-3m^3/s That is the answer need some solutions07: Water is flowing through apipe shown in Fig. what is the Difference in datum head (2₂-2₁), if the rate of flow through the pipe is (60 lit/sec). Jp Flookpo Ans: 2₂-2, -25.47m mm Datum line P₁ = 350kpa N 2Please make the solutions explicitly and simplify the finalanswer Thankyou. Given Variable: P (kN) = 52