A 12g bullet is fired horizontally against a 100 g wooden block resting on a rough horizontal surface, connected to a spring without a 150N/m constant mass If the bullet-block system compresses the spring 0.8m What was the speed of the bullet just entering the block?Assume that the coefficient of kinetic friction between the block and the surface is 0.6

Q: block 2 (mass 1.0 kg) is at rest on a frictionless surface and touching the end of an unstretched…

A:

Q: A 12.0-g bullet is fired horizontally into a 112-g wooden block that is initially at rest on a…

A: Given data *The mass of the bullet is m = 12.0 g = 0.012 kg *The mass of the wooden block is M = 112…

Q: A 10 g bullet is shot into a 500 g block, at rest on a frictionless horizontal surface. The bullet…

A: Given data: The mass of the bullet is m = 10 g. The mass of the block is M = 500 g. The…

Q: A 12.0-g bullet is fired horizontally into a 118-g wooden block that is initially at rest on a…

A: Since the collision is inelastic, only momentum of the system is conserved. Write the conservation…

Q: A 4.020-gram bullet is projected horizontally to a block of timber that rest on a horizontal floor.…

A: Given: The mass of the bullet is 4.020 g. The maximum displacement is 0.05 m. The spring constant is…

Q: frictionless

A: Given: Mass of the bullet = 10 g Mass of the block = 1.60 Kg Value of spring constant = 23.7 N/m…

Q: 0.350 kg block of wood rests on a horizontal frictionless surface and is attached to a spring (also…

A:

Q: A 12.0-g bullet is fired horizontally into a 109-g wooden block that is initially at rest on a…

A: mass of bullet (m) = 12 g mass of block (M) = 109 g Spring constant (k) = 144 Nmcompression in the…

Q: In the figure, block 2 (mass 1.10 kg) is at rest on a frictionless surface and touching the end of…

A: Given data:  Mass of block 2 (m2) = 1.10 kg Initial velocity of block 2 (V2) = 0 m/s Mass of block 1…

Q: A 0.122-kg dart is fired from a gun with a speed of 122 m/s horizontally into a 5.00-kg wooden…

A:

Q: You have been asked to design a "ballistic spring system" to measure the speed of bullets. A bullet…

A: m = 2.1 g M = 1.5 kg k = 40 N/m d = 0.15 m using conservation of energy (1/2)(M+m)(V)2 =…

Q: An agent fires a bullet into 4.5 kg wooden block resting in smooth surface and attached to a spring…

A: From the conservation of momentum, determine the speed of the bullet-block system after the bullet…

Q: A 4.020-gram bullet is projected horizontally to a block of timber that rest on a horizontal floor.…

A: Mass of bullet: m = 4.020 g = 4.020 x 10-3 kg Maximum displacement of the block: x = 0.0035 m Spring…

Q: 6. A 10.00-g bullet moving with an initial speed of 400.0 m/s is fired into and passes through a…

A:

Q: A 4.020-gram bullet is projected horizontally to a block of timber that rest on a horizontal floor.…

A: The maximum displacement of the block is when the kinetic energy of bullet was completely…

Q: A 15.00-g bullet moving with an initial speed of 415 m/s is fired into and passes through a 1.25-kg…

A:

Q: 15. A 1.0 kg ball is tied to the end of a 2.5 m string to form a pendulum. The pendulum is released…

A:

Q: 5.00-g bullet moving with an initial speed of 400 m/s is fired into and passes through a 1.00-kg…

A:

Q: 2. A 2.0-kg block of wood is attached to a horizontal spring that is at its equilibrium length (not…

A:

Q: 7. An object of mass m is compressed against a horizontal and ideal spring of constant k by amount…

A:

Q: A 0.454-kg block is attached to a horizontal spring that is at its equilibrium length, and whose…

A: According to Conservation of linear momentum Total Initial momentum = Total final momentum m1u1 +…

Q: A 15.00-g bullet moving with an initial speed 300.0 m/s is fired into and passes through a 3.00-kg…

A: For the block-spring system, during the compression process the energy conservation…

Q: A 12.0-g bullet is fired horizontally into a 114-g wooden block that is initially at rest on a…

A:

Q: A 0.80 kg block moves to the right with an initial velocity of 1.2 m/s and collides with spring with…

A: Mass of block: m = 0.80 kg Initial speed of block: u = 1.2 m/s Force constant of spring: k = 50 N/m…

Q: A 5.00-g bullet moving with an initial speed of v, = 460 m/s is fired into and passes through a…

A: Given data: Mass of the bullet, m =5.00 g =0.005 kg Initial speed vi =460 m/s Mass of the block, M…

Q: A 5.00-g bullet moving with an initial speed of vi = 380 m/s is fired into and passes through a…

A: (a)The bullet imparts a velocity v to the block on impact

Q: A 0.430 kg block of wood rests on a horizontal frictionless surface and is attached to a spring…

A: Using conservation of momentum, mu=m+Mvv=umm+M

Q: A 12.0-g bullet is fired horizontally into a 108-g wooden block that is initially at rest on a…

A:

Q: A 12.0-g bullet is fired horizontally into a 100-g woodenblock that is initially at rest on a…

A: Let v be the velocity of the bullet when it is fired, k be the spring constant, vi be the velocity…

Q: You have been asked to design a "ballistic spring system" to measure the speed of bullets. A bullet…

A: From conservation of momentum is, mBvB=mB+Mvf       ......(i) From conservation of energy,…

Q: A 12.0-g bullet is fired horizontally into a 107-g wooden block that is initially at rest on a…

A: according to the conservation of mechanical energy to block embedded bullet,…

Q: 7. Two masses, m1 = 2 kg and m2 = 8 kg, are pressed onto identical springs (k = 2 × 104 N/m) so that…

A:

Q: A 12.0-g bullet is fired horizontally into a 114-g wooden block that is initially at rest on a…

A: Use law of conservation of the energy into block-bullet embedded system, the expression for find…

Q: In the figure, block 2 (mass 1.10 kg) is at rest on a frictionless surface and touching the end of…

A: Given: The initial momentum of block-1.80 kg is: P1=m1×v1P1=1.80 kg×5.90 m/sP1=10.62 kg·m/s

Q: 5.00-g bullet moving with an initial speed of 400 m/s is fired into and passes through a 1.00-kg…

A:

Q: 3. A 1.5 kg block (moving in the right direction on a horizontal surface) collides with a spring…

A:

Q: A 10.0 g bullet is fired into and embeds itself in a 1.80 kg block attached to a spring with a…

A: The mass of the bullet is m=10 g The mass of the block is M=1.80 kg The spring constant is k=21.5…

Q: 5) A 0.420 kg block of wood rests on a horizontal frictionless surface and is attached to a spring…

A:

Q: In the figure, block 2 (mass 1.40 kg) is at rest on a frictionless surface and touching the end of…

A: Mass of block 2= M2 =1.40 kg  Mass of block 1=M1= 1.30 kg  Speed of block 1=V1= 3.10 m/s  Speed of…

Q: A 4.020-gram bullet is projected horizontally to a block of timber that rest on a horizontal floor.…

A: Given that, The mass of a bullet, m = 4.020-gram Initially, the bullet was at rest on a horizontal…

Q: One way to measure the speed of a bullet is to fire it into a block of wood attached to a spring.…

A: Here, the initial kinetic energy of the bullet is conserved into the kinetic energy of the…

Q: A 10.00-g bullet moving with an initial speed of 400.0 m/s is fired into and passes through a…

A: Given: The mas of the bullet is m=10 g. The initial speed is u=400 m/s. The spring constant is k=900…

Spring Potential Energy

The potential energy is the energy possessed by a body by virtue of its position or the energy held by the object due to its position relative to other objects, its force like stresses, charge, and other factors affecting the particles of the body. The potential energy is the measure of the net work done by or on the body. The spring potential energy is the potential energy stored due to the deformation of an elastic spring and this elasticity is due to the stretched spring. The elasticity is the ability of a solid-state matter to come back to its equilibrium position or original position after any kind of external force is acted on it. It is also known as Elastic potential energy. The potential energy here is caused due to the displacement of the spring from its equilibrium position to another position and this potential energy is equal to the net work done due to the stretching of the spring. It also resembles the same mechanics of the oscillation of a simple pendulum, where due to the external force, the object moves from its equilibrium position to its maximum ends and the periodic motion continues till it comes back to the equilibrium position to rest.