A 1,401.448 N painter needs to climb d=2.295 m up a ladder (measured along its length from the point where the ladder contacts the ground), without the ladder slipping. The uniform density ladder is 9.337 m long and weighs 250 N. It rests with one end on the ground and the other end against a smooth andfrictionless vertical wall. The ladder rises at an angle of theta=62.327º above the horizontal floor. What is the friction force in units of N that the floor must exert on the ladder? Use g = 9.8 m/s2.
A 1,401.448 N painter needs to climb d=2.295 m up a ladder (measured along its length from the point where the ladder contacts the ground), without the ladder slipping. The uniform density ladder is 9.337 m long and weighs 250 N. It rests with one end on the ground and the other end against a smooth andfrictionless vertical wall. The ladder rises at an angle of theta=62.327º above the horizontal floor. What is the friction force in units of N that the floor must exert on the ladder? Use g = 9.8 m/s2.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A 1,401.448 N painter needs to climb d=2.295 m up a ladder (measured along its length from the point where the ladder contacts the ground), without the ladder slipping. The uniform density ladder is 9.337 m long and weighs 250 N. It rests with one end on the ground and the other end against a smooth andfrictionless vertical wall. The ladder rises at an angle of theta=62.327º above the horizontal floor. What is the friction force in units of N that the floor must exert on the ladder? Use g = 9.8 m/s2.
Transcribed Image Text:painter position d
Ladder length
theta
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