A 150‑lbm astronaut took his bathroom scale (a spring scale) and a beam scale (compares masses) to the moon where the local gravity is g = 5.48 ft/s2. Determine how much he will weigh (a) on the spring scale and (b) on the beam scale.

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A: Given  Weight of rover W=3307 lb=3307*4.45=14716.15N g=32ft/s2=9.81 m/s2 gmoon=1.70m/s2

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A: The expression for mass in term of weight is m=Wg=W16gE

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A: Given data: Gravity on the moon, gM=1.6 m/s2 Mass of the astronaut, m=75 kg

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A: we know that  weight = mass * acceleration due to gravity

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A: The mass of the object, m=14 kg   The acceleration due to gravity, g=9.8 m/s2

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A: SOlution: Given that mass m =85 kg gravity g=3.7 m/s2

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Q: 1. A 120-lbm astronaut took his bathroom scale (a spring scale and a beam scale (compares masses))…

A: M = 120lbm g = 1.92m/s²

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A: Given: The mass of the person is 80 kg. The acceleration due to gravity is 13.7 m/s2.

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A: Mass (M) = 240.34 kg gravitational acceleration (g) = 9.81 m/s2

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A: mass = 30 lbm gmoon = 6 fts2gearth = 32 fts2

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Q: continue orbiting the Earth, but with a longer period

A: Refer attachment

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A: Dear student The force due to gravity acts downwards. This can be resolved into two components.

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Newton's First Law of Motion

If a very smooth ball is rolled down an inclined surface with zero friction, the ball will continue to roll indefinitely for an infinite time, in an attempt to reach to the same height on the opposite hill!