A 16 mm thick tension member is connected by two 6.25 mm spliced plates as shown. The tension member carries a service loads of dead load of 110 kN and a live load of 100 kN. 40, 80 , 40 , 40, 80 40 1625 mm 16 mm 1625 mm Fy 248 MPa Fu = 400 MPa Diam. of bolts = 16 mm Fnv = 300 MPa O Determine the nominal strength for one bolt due to shear. O Determine the nominal strength for one
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- Bottom chord of truss is composed of two angle bars each having a dimension of 151 mm x 198 mm x 7 mm. Between them is a gusset plate, 9.5mm thick. At each end of joints, four 19mm-dia. bolts are fastened along the gage line, having an edge distance of 38 mm and 55.8mm pitch. Use A36 steel Fy = 248 MPa Fu = 400 MPa spacing of bolt = 67.3 mm Compute the capacity of the bottom chord based on block shear strength, in KN.4. Considering sag rods and tie rods at midspan, what is the required diameter of sag rods in mm? (rounded value) A 20m Fink Truss are spaced at 'S' meters o.c. the purlins are made up of C10X20 sections and are spaced 1.1967m on centers. The truss has a height of 4m. Roof LL is 'RLL' N/m2 of roof surface and roof covering is assumed to be 'RDL' N/m2 of roof surface. Determine whether the purlins are adequate to carry such loadings. Fy = 248 MPa. C10X20 properties: w=29.76kg/m, A=3787.09mm2, Ix=32.84x106mm4, Iy=1.17x106mm4, Zx=317.91x103mm3, Sx=258.92x103mm3, Zy=44.25x103mm3, Sy=21.47x103mm3 S (m) RLL (N/m^2) RDL (N/m^2) 6.00 900 900The riveted lap connection shown consists of two(2) – PL 12 mm × 280 mm. 1. If allowable bearing stress in holes is 1.2Fu where Fu is the ultimate strength of the plate and which is equal to 400 MPa, find the maximum allowable force P that can be applied neglecting effect of eccentricity. a. 563.3 kN b. 460.8 kN c. 683. 6 kN d. 405.9 kN 2. If allowable yielding of gross area is Fy/1.67, where Fy is the yield strength of the plate and which is equal to 250 MPa, find the maximum allowable force P that can be applied neglecting effect of eccentricity. a. 534 kN b. 560 kN c. 446 kN d. 503 kN 3. If diameter of hole equals diameter of rivet, what is the net area of edge-3-4-edge in square millimeters? a. 2540 b. 2590 c. 2880 d. 2040
- Simply Supported Beam ABCDE below carries multiple loads as shown. A built-upsection made from a T-Section and a Channel (C-Section) fastened together by 16mm∅ bolts,equally spaced from the center of the section, with shearing capacity τ=100 MPa, for bearing σb= 220 MPa for rivets in single shear and σb = 280 MPa for rivets in double shear. E=200GPa forall materials. 4. Determine the location of the centroid, in mm, from the left of the section.5. Determine the moment of inertia of the section in x106mm4.6. Determine the moment capacity of the section, kN-m, if fbcap≤300 MPa.The figure shows a roof truss and the detail of the connection at joint G. Members BG and CG are angle sections with the thicknesses shown in the The working stresses are 70 MPa for shear in the rivets and 140 MPa for bearing stress due to the rivets. How many 25-mm-diameter rivets are required to fasten the following members to the gusset plate: (a) BG; and (b) CG?8. Considering sag rods and tie rods at third points, what is the required diameter of sag rods? (rounded value) A 20m Fink Truss are spaced at 'S' meters o.c. the purlins are made up of C10X20 sections and are spaced 1.1967m on centers. The truss has a height of 4m. Roof LL is 'RLL' N/m2 of roof surface and roof covering is assumed to be 'RDL' N/m2 of roof surface. Determine whether the purlins are adequate to carry such loadings. Fy = 248 MPa. C10X20 properties: w=29.76kg/m, A=3787.09mm2, Ix=32.84x106mm4, Iy=1.17x106mm4, Zx=317.91x103mm3, Sx=258.92x103mm3, Zy=44.25x103mm3, Sy=21.47x103mm3 S (m) RLL (N/m^2) RDL (N/m^2) 6.00 900 900
- The figure shows a truss and the detail of the riveted connection at joint H. Using allowable stresses ofτ = H MPa and σb= I MPa, how many 19-mm diameter rivets are required to fasten member HB to thegusset plate? Member HC? Round-up your answer to a whole number F=162 H=110 I= 180A double channel shape is used as a tension member. The channels are bolted to a gusset plate with 22mm diameter bolts.Fy-channel = 345 MPa, Fu-channel = 450 MPaFy-plate = 248 MPa, Fu-plate = 400 MPaAchannel = 3555 mm^2, tw = 12.18 mm,Shear lag factor = 0.90A. Determine the ultimate tensile strength of the tension member based on its gross area.B. Determine the allowable tensile strength of the tension member based on its gross area.C. Determine the ultimate tensile strength of the tension member based on its net area.D. Determine the allowable tensile strength of the tension member based on its net areaan angle bar 100x100x11 mm tension member is connected with 20-mm-dia bolts as shown in the fig. both legs of the angles are connected. use fy=248 MPa and Fu=400 MPa. 1. determine the nominal strength for tensile yielding in the gross section. a. 515.59 kN b. 429.67 kN c. 545.60 kN d. 390.10 kN 2. determine the effective net area of member a. 1573 mm^2 b. 1632 mm^2 c. 1605 mm^2 d. 1815 mm^2 3. determine the nominal strength for tensile rupture in the net area. a. 642 kN b. 730 kN c. 554 kN d. 650 kN
- For the clevis connection shown, determine the shear stress in the 20-mm-diameter bolt for an applied load of P = 130 kN.WT8x50 11 at a spacing of 3” and placed in gr$ 12x ²4 " Plate with eight 7/8" bolts. ½ bolts. two rows, Please determine the shear lag factor (consider case 2 & case 7) and Ae of WT8850.A lap joint consists of two the same plates with a width of 75 mm and a thickness of 11 mm. it is inter-connected by 4 – 20 mm diameter rivets spaced at equal intervals. Allowable shearing and bearing stresses of the rivets are 110 and 220 MPa respectively.Using A36 steel with Fy = 248 MPa and assuming diameter of hole 3 mm bigger than therivets,a. Determine the capacity due to shear of bolts. b. Determine the capacity due to bearing of rivets on the plates?