A 185.0 mL solution of 2.234 M strontium nitrate is mixed with 215.0 mL of a 2.901 M sodium fluoride solution. Calculate the mass of the resulting strontium fluoride precipitate. mass: Assuming complete precipitation, calculate thế final concentration of each ion. If the ion is no longer in solution, enter a 0 for the concentration. [Na*] = [NO,] = MN

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A: Formula used :-  Number of moles(n) = concentration (mol/L) × volume (L)

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Q: Barium chromate, BaCrO4(s), is an insoluble yellow solid. Calculate the mass of barium chromate that…

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Q: A 165.0 mL solution of 2.925 M strontium nitrate is mixed with 220.0 mL of a 3.22I M sodium fluoride…

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Q: Fe(II) can be precipitated from a slightly basic aqueous solution by bubbling oxygen through the…

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Q: Potassium iodide reacts with lead(II) nitrate in the following precipitation reaction: 2 KI(aq) +…

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Q: A 180.0 mL solution of 2.927 M strontium nitrate is mixed with 205.0 mL of a 3.897 M sodium fluoride…

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