Problem 1:A 2.0 m wide strip foundation is placed in sand at 1.0 m depth. The properties of the sand are: y = 19kN/m, c'= 0, and D' = 30°. Determine the allowable net wall load that the foundation can carry, with afactor of safety of 3.0, using Terzhagi bearing capacity equation (see lecture).

Given, Width of strip = 2 m Depth of foundation = 1 m Bulk unit weight of sand = 19 kN/m3 Factor of…

A 2.0 m wide strip foundation is placed in sand at 1.0 m depth. The properties of the sand are: y = 19 kN/m³, c'= 0, and ¤' = 30°. Determine the allowable net wall load that the foundation can carry, with a factor of safety of 3.0, using Terzhagi bearing capacity equation (see lecture).

A 2.0 m wide strip foundation is placed in sand at 1.0 m depth. The properties of the sand are: y = 19 kN/m³, c'= 0, and ¤' = 30°. Determine the allowable net wall load that the foundation can carry, with a factor of safety of 3.0, using Terzhagi bearing capacity equation (see lecture).

Principles of Foundation Engineering (MindTap Course List)

9th Edition

ISBN:9781337705028

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter6: Shallow Foundations: Ultimate Bearing Capacity

Section: Chapter Questions

Problem 6.6P: A 2.0 m wide continuous foundation carries a wall load of 350 kN/m in a clayey soil where = 19.0...

See similar textbooks

Related questions

Q: Calculate the settlement under the center of a flexible foundation 4 m by 4 m due to volume…

A: Given data:

Q: A long foundation 0.6 m wide carries a line load of 100 kN/m. Calculate the vertical stressi ncrease…

A: solution given line load q = 100Kn/m given point x = 2.5mz=1.5mthe increase in verticle stress due…

Q: A Im deep foundation is placed on a soil of unit weight 20 kN/m³ and ultimate bearing capacity of…

A: Given: Foundation depth, D = 1 m Unit weight of soil, γ = 20 kN/m3 Ultimate bearing capacity, qu =…

Q: For a flexible foundation with sides 2 m and 3 m and an axial load of 750 kN, determine the elastic…

A: Given- Length of footing L=3 mwidth of footing B=2 mAxial load P=750 kNpoisson's ratio v=0.37E=9.8…

Q: It is planned to construct a rectangular foundation with base dimensions of 8 * 14 m (B* L) on the…

Q: A 2.0 m wide strip foundation is placed in sand at 1.0 m depth. The properties of the sand are: y =…

Q: For a square foundation, according to the information given and the assumption of vertical load, it…

Q: The shallow foundation shown in Figure 6.25 measures 1.5 m × 2.25 m and is subjected to a centric…

A: Given: The unit weight is 17 kN/m3. The factor of safety is 4.

Q: If the total transferred load of the soil for an unreinforced wall foundation is 100 kN/m, the…

A: Given: The total load is 100 kN/m. The bearing capacity of the soil is 80 kPa. The wall thickness is…

Q: A 2.0m wide continuous foundation carries a wall load of 350 kN/m in a clayey soil where y 19,0…

A: Given information:

Q: For an eccentrically loaded continuous foundation on sand, given B = 1.53 m, Df = 1.59 m, e/B = 0.15…

A: To determine the ultimate load per unit length for the eccentrically loaded continuous foundation.…

Q: The shallow foundation shown in Figure 4.24 measures 1.5 m x 2.25 m and is subjected to a centric…

A: Given:- 1.5m x 2.25 meB=0.12 meL=0.36md=0.8mFOS=4γ=17kN/m3∅=35oc'=0To find:-allowable load the…

Q: Question attached

A: The given data is: eL=0.3 mB=1.5 meB=0.15 mL=1.5 m

Q: For an eccentrically loaded continuous foundation on sand, given B = 2.35 m, Df = 1.78 m, e/B = 0.17…

Q: Question attached

A: Width of footing = B = 2m Depth of footing = Df = 1m Unit weight of soil = γs = 19.5 KNm3…

Q: Q2) Find the increasing stress (Ao) at point A, at depth 6 m below the corner of the footing of…

A: The stress increment at any depth z and radial distance r below the loaded area is calculated using…

Q: For the design of an eccentrically loaded shallow foundation, given the following: Soil: y = 19…

Q: A 2.0 m wide square foundation is placed at 0.5 m depth in a saturated clay where cu= 40 kN/m2 and…

A: Given :- Width of the foundation (b) = 2 m Depth of the foundation (h) = 0.5 m Cu = 40 kN/m2 Unit…

Q: A square foundation of 5 m x 5 m is to be founded at a depth of 3 m in a deep layer of sand of unit…

A: (i) For ϕ=25° Refer the table for Terzaghi bearing capacity factors, we get Nc=25.1Nq=12.7Nγ=9.7

Q: The square foundation with 2.0 m width was built close to the slope and causes an increase in…

A: depth of the beam is not given Assume depth of the foundation H=2.0 mcohesion for the soil C=0 and…

Q: A square foundation in a sand deposit measures 4 ft x 4 ft in plan. Given: Df = 5 ft, soil friction…

A: Given, Size of foundation = 4ft×4ftDepth of foundation, Df = 5 ftAngle of friction, ϕ = 35oUnit…

Q: The soil is having unit weight of 20 kN/m³ and depth of foundation is equal to 1.2 m, If the net…

A: given unit weight=20 kN/m3depth d=1.2 mnet bearing capacity=2532 kN/m2FOS=3

Q: Question attached

A: Given: The width of the footing is 2 m. The depth is 1.5 m. The cohesion of the soil is 20 kN/m2.…

Q: A square foundation is 1.5 m X 1.5 m in plan. Given the soil properties supporting the foundation…

Q: 3. Assuming the load exerted (P) by the foundation is 5,000,000 lbs., determine I4, q, and the…

A: Given:- The magnitude of the load = P = 5,000,000 lbs The depth = 10 ft To determine:- The value of…

Q: H.Q 1 Consider a rectangular foundation. Given: B = 1.5 m, L = 2.5 m, Df = 1.2 m, H =0.9 m, o' =…

A: The given data is as follows: Rectangular foundation,B=1.5 mL=2.5 mDf=1.2 mH=0.9 mϕ'=40∘c'=0γ=17…

Q: An eccentrically loaded foundation is shown in Figure P3.9. Use FS of 4 and determine the maximum…

Q: A continuous foundation with a width of 1 m is located on a slope made of clay soil. Refer to Figure…

A: Solution Given Data Df = 1 m, H = 4 m, b = 2 m, γ = 16.8 kN/m3, c = cu = 68 kN/m2, Φ= 0, β = 60°.

Q: A 10 m X 8 m mat foundation is to be placed at 3 m depth in a saturated clay where c, Determine the…

Q: A 2 m wide continuous foundation is placed at 1 m depth within a 1.5 m thick sand layer that is…

A: Given:- The width of the foundation = B = 2 m The depth of the foundation = Df = 1 m The thickness…

Q: Using the general bearing capacity equation, compute the ultimate load (in kN) that a 2.53 x 4.66…

A: size of the footing= 2.53×4.66m cohesion (c)=20.79 kN/m2 angle of internal friction (ϕ)= 27°…

Q: " (a) Qu 3 10 B (b) M M → X M₁ Q.₁ (c) M₁ Qu (d) Figure 4.24 Analysis of foundation with two-way…

Q: A square column foundation has to carry a gross allowable load of 1805 kN ( FS = 3). Given: D f =…

A: Given: The load on the column is 1805 kN. The factor of safety is 3. The depth of the footing is 1.4…

Q: 2 metre wide continuous Foundation carries a will load of 350 kilo Newton per metre square in a…

A: Solution Given Data ϕ=230 q=350 KN/m2 B=2 m

Q: For an eccentrically loaded continuous foundation on sand, given B = 1.9m, Df = 0.81m, e/B = 0.21…

Q: Que a) A square foundation is 2.5 m * 2.5 m in plan. The soil supporting the foundation has an…

Q: A strip footing foundation 1 m wide is constructed in the slope of a hill whose surface inclination…

A: Given data:

Q: EXAMPLE 7.14 A rectangular foundation in a saturated clay measures 1.5 m x 3 m. Given: D; = 1.8 m,…

A: Ultimate uplift capacity can be calculated by using Terzaaghi's and Skempton's theory.Here we are…

Q: H.Q 2 A square foundation measuring 1.5 m x 1.5 m is supported by a saturated clay layer of limited…

Q: A 2.0 m wide strip foundation is placed in sand at 1.0 m depth. The properties of the sand are: =…

A: Given,width of foundationB=2mdepthDf=1munit weight of soilγ=19.5KN/m3C'=0ϕ'=34°using meyerhof's…

Q: For an eccentrically loaded continuous foundation on sand, given B = 1.92 m, Df = 1. m, e/B = 0.11…

Q: A square foundation is 1.5 m X 1.5 m in plan. Given the soil properties supporting the foundation…

A: Data is as given General shear failure

Q: With respect to Hansen's equations, for a square foundation that is BxB in plan (B=3 m), Df = 2 m, y…

Q: A 2 m wide continuous foundation is placed at 1 m depth within a 1.5 m thick sand layer that is…

A: Given: The width of the foundation is B=2 m. The depth of the foundation is Df=1 m. The thickness of…

Q: subject : Geotechnical DesignBook : PRINCIPLE OF FOUNDATION ENGINEERING

A: We have been given the following data:

Q: subject : Geotechnical Design Book : PRINCIPLE OF FOUNDATION ENGINEERING

A: We have been given the following information:

Q: A water tank is required to be constructed with a circular foundation having a diameter of 20m…

A: Answer Given Diameter of water tank=20 m Pictorial representation of given condition of water tank -…

Concept explainers

Load and resistance factor design

Load and resistance factors design (LRFD), also known as Limit state design (LSD), refers to the design method used in building engineering. A boundary condition is a condition of a structure where it can no longer meet the relevant design requirements. The condition may refer to the load level or other actions on the structure, while the terms refer to the integrity of the structure, suitability for use, durability, or other design requirements. A structure designed for LRFD is limited to keeping track of all possible actions during its design time and is always ready for use, with the appropriate level of reliability in each boundary condition. LRFD-based construction codes clearly define the appropriate levels of reliability in their instructions.

Question

Problem 1:
A 2.0 m wide strip foundation is placed in sand at 1.0 m depth. The properties of the sand are: y = 19
kN/m, c'= 0, and D' = 30°. Determine the allowable net wall load that the foundation can carry, with a
factor of safety of 3.0, using Terzhagi bearing capacity equation (see lecture).

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Step 4

Trending now

This is a popular solution!

Step by step

Solved in 4 steps with 4 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

A 2.0 m wide continuous foundation carries a wall load of 350 kN/m in a clayey soil where = 19.0 kN/m3, c = 5.0 kN/m2, and = 23. The foundation depth is 1.5 m. Determine the factor of safety of this foundation using Eq. (6.28).
A square column foundation has to carry a gross allowable load of 1805 kN (FS = 3). Given: Df = 1.5 m, =15.9 kN/m3, = 34, and c = 0. Use Terzaghis equation to determine the size of the foundation (B). Assume general shear failure.
Consider a continuous foundation of width B = 1.4 m on a sand deposit with c' = 0, Φ' = 38° and γ = 17.5 kN/m3. The foundation is subjected to an eccentrically inclined load (see Figure 4.31). Given: load eccentricity e = 0.15 m, Df = 1 m, and load inclination β = 18°. Estimate the failure load Qu(ei) per unit length of the foundation a. for a partially compensated type of loading [Eq. (4.85)] b. for a reinforced type of loading [Eq. (4.86)]
A circular foundation of 1.5 m diameter is constructed in a sand deposit. Given: Df =1 5 m, soil friction angle Ø =35o and soil unit weight γ =17 4kN/m3. Estimate the ultimate uplift capacity of the foundation.
In the following exercise, the load capacity (Qu) per meter of length must be calculated for a continuous foundation that has an eccentricity e=1.2m in the width direction of the foundation.
The shallow foundation shown in Figure 6.25 measures 1.5 m × 2.25 m and is subjected to a centric load and a moment. If eB = 0.12 m, eL = 0.36 m, and the depth of the foundation is 0.8 m, determine the allowable load the foundation can carry. Use a factor of safety of 4. For the soil, we are told that unit weight γ = 17 kN/m3, friction angle ф′ = 35°, and cohesion c′ = 0.
A square foundation is 1.5m x 1.5m in plan. The soil supporting the foundation has a friction angle '=20 and c'=15.2 kN/m². The unit weight of soil is y=17.8 kN/m². Determine the allowable gross load on the foundation with a factor of safety F,=4. Assume that the depth of the foundation D=1m and the general shear failure occur in the soils mass.
A 1m deep foundation is placed on a soil of unit weight 20 kN/m3 and ultimate bearing capacity of 300 kN/m2. Determine the net safe bearing capacity for a factor of safety of 2.5
It is proposed to place a 9 ft 9 ft foundation at 6 ft depth in a sandy soil, where the average N60 is 25 and the unit weight is 115.0 lb/ft3. Using Meyerhofs expressions presented in Section 9.6, estimate the allowable net pressure that would give 1.2 in. of settlement.
The shallow foundation shown in Figure 4.24 measures 1.5 m x 2.25 m and is subjected to a centric load and a moment. If eB = 0.12 m, eL = 0.36 m, and the depth of the foundation is 0.8 m, determine the allowable load the foundation can carry. Use a factor of safety of 4. For the soil, we are told that unit weight γ = 17 kN/m3, friction angle Φ' = 35°, and cohesion c' = 0.
A square column foundation has to carry a gross allowable load of 1805 kN ( FS = 3). Given: D f = 1.4 m, γ = 15.4 kN/m 3 , ϕ ′ = 34 ° , and c ′ = 0. Use Terzaghi's equation to determine the size of the foundation ( B ). Assume general shear failure.
A continuous foundation with a width of 1 m is located on a slope made of clay soil. Refer to Figure 5.19 and let Df = 1 m, H = 4 m, b = 2 m, γ = 16.8 kN/m3, c = cu = 68 kN/m2, Φ= 0, and β = 60°.a. Determine the allowable bearing capacity of the foundation. Let FS = 3.b. Plot a graph of the ultimate bearing capacity qu if b is changed from 0 to 6 m.