2. A 2.0 mili grams particle with electric charge of +80.0 µC orbits a charged wire, making12000 revolutions per second. The radius of the orbit is 1.0 cm and length of the wire is75.0 cm. What is the wire's linear charge density?

Given that: m=2 mili grams= 2×10-3 g =2×10-6 kgq=+80.0 μC=80.0×10-6 Cω=12000 rev/sec=12000×2π=24000π…

Answered: A 2.0 mili grams particle with electric…

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter19: Electric Forces And Electric Fields

Section: Chapter Questions

Problem 30P

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2. A 2.0 mili grams particle with electric charge of +80.0 µC orbits a charged wire, making
12000 revolutions per second. The radius of the orbit is 1.0 cm and length of the wire is
75.0 cm. What is the wire's linear charge density?

Expert Solution

Step 1

Given that:

$m = 2 m i l i g r a m s = 2 \times 10^{- 3} g = 2 \times 10^{- 6} k g q = + 80.0 μ C = 80.0 \times 10^{- 6} C ω = 12000 r e v / s e c = 12000 \times 2 π = 24000 π r a d / s e c r = 1 c m = 0.01 m L = 75 c m = 0.75 m L e t c h a r g e d e n s i t y o f t h e w i r e i s λ C / m$

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