In the figure a thin glass rod forms a semicircle of radius r = 4.74 cm. Charge is uniformly distributed along the rod, with +q = 4.39 pC inthe upper half and -q = -4.39 pC in the lower half. What is the magnitude of the electric field at P, the center of the semicircle?P.NumberiUnits

Given: r=4.74cm = 0.0474 mq = 4.39 pC = 4.39*10-12 C

In the figure a thin glass rod forms a semicircle of radius r = 4.74 cm. Charge is uniformly distributed along the rod, with +q - 4.39 pC i the upper half and -q = -4.39 pC in the lower half. What is the magnitude of the electric field at P, the center of the semicircle? Number i Units

In the figure a thin glass rod forms a semicircle of radius r = 4.74 cm. Charge is uniformly distributed along the rod, with +q - 4.39 pC i the upper half and -q = -4.39 pC in the lower half. What is the magnitude of the electric field at P, the center of the semicircle? Number i Units

Physics for Scientists and Engineers with Modern Physics

10th Edition

ISBN:9781337553292

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter23: Continuous Charge Distributions And Gauss's Law

Section: Chapter Questions

Problem 33P: A solid sphere of radius 40.0 cm has a total positive charge of 26.0 C uniformly distributed...

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