A +2.20 nC charge particle is released from rest and moves in a straight line in the direction of left a distance 6.00 cm between points a and b in a uniform electric field E directed to the left. After it reached to the point b, its kinetic energy is +2.20 × 10° J. (a) Determine the work done by the electric force, (b) What is the potential of the point a with respect to A point b? (c) What is the magnitude of E ?

A +2.20 nC charge particle is released from rest and moves in a straight line in the direction of left a distance 6.00 cm between points a and b in a uniform electric field E directed to the left. After it reached to the point b, its kinetic energy is +2.20 × 10° J. (a) Determine the work done by the electric force, (b) What is the potential of the point a with respect to A point b? (c) What is the magnitude of E ?

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter20: Electric Potential And Capacitance

Section: Chapter Questions

Problem 11P: The three charged particles in Figure P20.11 are at the vertices of an isosceles triangle (where d =...

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A filament running along the x axis from the origin to x = 80.0 cm carries electric charge with uniform density. At the point P with coordinates (x = 80.0 cm, y = 80.0 cm), this filament creates electric potential 100 V. Now we add another filament along the y axis, running from the origin to y = 80.0 cm, carrying the same amount of charge with the same uniform density. At the same point P, is the electric potential created by the pair of filaments (a) greater than 200 V, (b) 200 V, (c) 100 V, (d) between 0 and 200 V, or (e) 0?
The three charged particles in Figure P20.11 are at the vertices of an isosceles triangle (where d = 2.00 cm). Taking q = 7.00 C, calculate the electric potential at point A, the midpoint of the base. Figure P20.11
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A proton is released from rest at the origin in a uniform electric field in the positive x direction with magnitude 850 N/C. What is the change in the electric potential energy of the protonfield system when the proton travels to x = 2.50 m? (a) 3.40 1016 J (b) 3.40 1016 J (c) 2.50 1016 J (d) 2.50 1016 J (e) 1.60 1019 J
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