A 2.65 g sample of colorless crystal was vaporized in a 255 mL flask at 123°C and 1.0455 atm. What is the molecular weight of this substance?

Chemistry: Matter and Change
1st Edition
ISBN:9780078746376
Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Chapter13: Gases
Section13.1: The Gas Laws
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A 2.65 g sample of colorless crystal was vaporized in a 255 mL flask at 123°C and 1.0455 atm. What
is the molecular weight of this substance?
Transcribed Image Text:A 2.65 g sample of colorless crystal was vaporized in a 255 mL flask at 123°C and 1.0455 atm. What is the molecular weight of this substance?
Expert Solution
Step 1 ideal gas equation

PV = nRT 

PV = (w/M) RT   

( mole (n)= mass/molarmass)

Where 

P= 1.0455 atm , w= 2.65 g

V = 255 mL × 1L/1000 mL = 0.255 L 

R = 0.0821 Latm/mol.k 

T = 123 +273K = 396 K

 

 

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