A 20-ft ladder is leaning against a building. If the bottom of the ladder is pulled away fromthe building at ,how fast is the top of the ladder moving down when the top is 10 ft from3 ft2 s3√/3 ftthe ground? Ans:2 sdydt==

Length of the ladder= 20 ft Speed of the bottom of the ladder=3/2 ft/s

A 20-ft ladder is leaning against a building. If the bottom of the ladder is pulled away from 3 ft the building at how fast is the top of the ladder moving down when the top is 10 ft from 2 s dy the ground? Ans: dt == 3√√/3 ft 2 s

A 20-ft ladder is leaning against a building. If the bottom of the ladder is pulled away from 3 ft the building at how fast is the top of the ladder moving down when the top is 10 ft from 2 s dy the ground? Ans: dt == 3√√/3 ft 2 s

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter5: More Applications Of Newton’s Laws

Section: Chapter Questions

Problem 7OQ: A door in a hospital has a pneumatic closer that pulls the door shut such that the doorknob moves...

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Concept explainers

Angular speed, acceleration and displacement

Angular acceleration is defined as the rate of change in angular velocity with respect to time. It has both magnitude and direction. So, it is a vector quantity.

Angular Position

Before diving into angular position, one should understand the basics of position and its importance along with usage in day-to-day life. When one talks of position, it’s always relative with respect to some other object. For example, position of earth with respect to sun, position of school with respect to house, etc. Angular position is the rotational analogue of linear position.

Question

A 20-ft ladder is leaning against a building. If the bottom of the ladder is pulled away from
the building at ,how fast is the top of the ladder moving down when the top is 10 ft from
3 ft
2 s
3√/3 ft
the ground? Ans:
2 s
dy
dt
==

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