  # A 21.0-kg block is initially at rest on a horizontal surface. A horizontal force of 79.0 N is required to set the block in motion, after which a horizontal force of 65.0 N is required to keep the block moving with constant speed.a) Find the coefficient of static friction between the block and the surface.b) Find the coefficient of kinetic friction between the block and the surface.

Question

A 21.0-kg block is initially at rest on a horizontal surface. A horizontal force of 79.0 N is required to set the block in motion, after which a horizontal force of 65.0 N is required to keep the block moving with constant speed.

a) Find the coefficient of static friction between the block and the surface.

b) Find the coefficient of kinetic friction between the block and the surface.

check_circleExpert Solution
Step 1

Write the expression for static frictional force that sets the block in motion

Step 2

Substituting the values

Step 3

Write the expression for the kinetic frictional force...

### Want to see the full answer?

See Solution

#### Want to see this answer and more?

Solutions are written by subject experts who are available 24/7. Questions are typically answered within 1 hour*

See Solution
*Response times may vary by subject and question
Tagged in

### Friction 