A 25.00 mL sample of methanoic (HCHO2, Ka = 1.8 x 10-4) is titrated to the equivalence point using 18.00 mL of 0.800 mol/L sodium hydroxide. What is the pH of the resulting solution?
A 25.00 mL sample of methanoic (HCHO2, Ka = 1.8 x 10-4) is titrated to the equivalence point using 18.00 mL of 0.800 mol/L sodium hydroxide. What is the pH of the resulting solution?
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter15: Solutions Of Acids And Bases
Section: Chapter Questions
Problem 15.121QE: A solution is made by diluting 25.0 mL of concentrated HCl (37% by weight; density = 1.19 g/mL) to...
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A 25.00 mL sample of methanoic (HCHO2, Ka = 1.8 x 10-4) is titrated to the equivalence point using 18.00 mL of 0.800 mol/L sodium hydroxide. What is the pH of the resulting solution?
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