A 3-phase, 416-V, 50-Hz, 35 HP, 6-pole, Y-connected induction motor has the following per phase parameters in ohms per-phase referred to the stator side: R, = 0.08 Q, R2 = 0.05 Q, X, = 0.32 Q , X2 = 0.4 Q ,XM = 10 Q The total friction, windage, and core losses can be assumed to be constant at 3 KW, independent of load. For a 5% slip, when the motor is operating at 416 V, 50 Hz, Find the stator input line current. Select one: O a. None O b. I1 = 188.4L-38.5° A O c. I = 326.3L-38.2° A O d. l1 = 257.3L-31.8° A Clear my choice

A 3-phase, 416-V, 50-Hz, 35 HP, 6-pole, Y-connected induction motor has the following per phase parameters in ohms per-phase referred to the stator side: R, = 0.08 Q, R2 = 0.05 Q, X, = 0.32 Q , X2 = 0.4 Q ,XM = 10 Q The total friction, windage, and core losses can be assumed to be constant at 3 KW, independent of load. For a 5% slip, when the motor is operating at 416 V, 50 Hz, Find the stator input line current. Select one: O a. None O b. I1 = 188.4L-38.5° A O c. I = 326.3L-38.2° A O d. l1 = 257.3L-31.8° A Clear my choice

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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An approximate per phase equivalent circuit of a 3-phase, 220-V, wye-connected, 6 pole, 60 Hz induction motor is shown in figure below for which R1 = 0.3 ohm; X1 = 0.4 ohm; R’2 = 0.4 ohm; X’2 = 0.6 ohm; Xm = 15 ohms. For the given numerical values calculate the total developed(electromagnetic) torque in (kg-cm) .The motor speed is 1080 rpm.
The equivalent circuit parameters per phase of a 3-phase, star-connected, 220V, 7.5 kW, 60Hz, 6-pole induction motor are as follows. Total friction-ventilation losses are 403 W. for 2% slip; R1=0.294 R2=0.144 X1=0.503 X2=0.209 Xm=13.25 Find the impedance, speed, shaft torque, output power, stator current, power factor and efficiency values.
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A 440V, 60Hz, 10 pole delta connected induction motor is rated at 100KW. The equivalent parameter for the motor are: Rs = 0.15 Ω R2` = 0.15 Ω Xs = 0.3 Ω X2` = 0.2 Ω Xm = 6 Ω R c = 120 Ω At full load condition, the friction and windage losses are 600W. The slip of the motor is 0.04. Calculate: The stator line current Is ? The input power ? Stator copper losses ? The air gap power PG ? The converted power Pconv? The torque induced by the motor ? The load torque ? The starting torque? The efficiency of the motor ?