A 3.0-m rod is pivoted about its left end. A force of 6.0 N is applied perpendicular to the rod at a distance of 1.2 m from the pivot causing a counter clockwise torque, and a force of 5.2 N is applied at the end of the rod 3.0 m from the pivot. The 5.2 N is at an angle of 30° to the rod and causes a clockwise torque. What is the net torque about the pivot? 15 N.m 0 N.m -6.3 N.m -0.6 Nxm B D

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
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Chapter10: Rotational Motion
Section: Chapter Questions
Problem 14OQ: A rod 7.0 m long is pivoted at a point 2.0 m from the left end. A downward force of 50 N acts at the...
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A 3.0-m rod is pivoted about its left end. A force of 6.0 N is applied perpendicular to the rod at a distance of 1.2 m from the pivot
causing a counter clockwise torque, and a force of 5.2 N is applied at the end of the rod 3.0 m from the pivot. The 5.2 N is at an angle of
30° to the rod and causes a clockwise torque. What is the net torque about the pivot?
A
15 N.m
B
0 N.m
-6.3 N.m
-0.6 Nxm
D
Transcribed Image Text:A 3.0-m rod is pivoted about its left end. A force of 6.0 N is applied perpendicular to the rod at a distance of 1.2 m from the pivot causing a counter clockwise torque, and a force of 5.2 N is applied at the end of the rod 3.0 m from the pivot. The 5.2 N is at an angle of 30° to the rod and causes a clockwise torque. What is the net torque about the pivot? A 15 N.m B 0 N.m -6.3 N.m -0.6 Nxm D
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