A 48.0−g sample of an unknown metal at 99°C was placed in a constant-pressure calorimeter containing 90.0 g of water at 24.0°C. The final temperature of the system was found to be 28.4°C. Calculate the specific heat of the metal. (The heat capacity of the calorimeter is 11.4 J/°C.)

Question
Asked Oct 27, 2019

A 48.0−g sample of an unknown metal at 99°C was placed in a constant-pressure calorimeter containing 90.0 g of water at 24.0°C. The final temperature of the system was found to be 28.4°C. Calculate the specific heat of the metal. (The heat capacity of the calorimeter is 11.4 J/°C.)

check_circleExpert Solution
Step 1

Given data:

Mass of sample metal 48.0 g
Mass of water = 90.0 g
Temperature of metal 99 °C
Temperature of calorimeter
24 °C
Final temperature of system = 28.4 °C
Heat capacity of calorimeter 11.4 J/oC
help_outline

Image Transcriptionclose

Mass of sample metal 48.0 g Mass of water = 90.0 g Temperature of metal 99 °C Temperature of calorimeter 24 °C Final temperature of system = 28.4 °C Heat capacity of calorimeter 11.4 J/oC

fullscreen
Step 2

Heat lost by metal=heat gain by water and calorimeter.

Therefore,

-m( ealorimeter
m_(AT ()= m(AT,)(s,)+ Ce(AT,).
()
w
Where
is the mass of metal
mis the mass of water
S m is the specific heat of metal.
is the specific heat of water (4.186 J/g. °C)
Ceal is the heat capacity of the calorimeter
AT change in temperature.
help_outline

Image Transcriptionclose

-m( ealorimeter m_(AT ()= m(AT,)(s,)+ Ce(AT,). () w Where is the mass of metal mis the mass of water S m is the specific heat of metal. is the specific heat of water (4.186 J/g. °C) Ceal is the heat capacity of the calorimeter AT change in temperature.

fullscreen
Step 3

Substitute all the given values in ...

-m (AT,) ( 5) = m. (AT, ) (5,) +C (AT)
W
J
90.0 g (28.4 C -24 °C)4.186
g oC
-48 g (28.4 °C-99 °C)s
J
:(28.4°C-24 °C)
° C
+11.4
3388.8 g oC(s=1657.656 J
50.16 J
m
1707.816
S
m
3388.8 g.°C
J
=0.504
g. °C
help_outline

Image Transcriptionclose

-m (AT,) ( 5) = m. (AT, ) (5,) +C (AT) W J 90.0 g (28.4 C -24 °C)4.186 g oC -48 g (28.4 °C-99 °C)s J :(28.4°C-24 °C) ° C +11.4 3388.8 g oC(s=1657.656 J 50.16 J m 1707.816 S m 3388.8 g.°C J =0.504 g. °C

fullscreen

Want to see the full answer?

See Solution

Check out a sample Q&A here.

Want to see this answer and more?

Solutions are written by subject experts who are available 24/7. Questions are typically answered within 1 hour*

See Solution
*Response times may vary by subject and question
Tagged in

Science

Chemistry

Related Chemistry Q&A

Find answers to questions asked by student like you

Show more Q&A add
question_answer

Q: How do I find the mass of water and volume of water that are empty. I know the formulas but which nu...

A: All the calculations are done for trial 1 only. The density of water (d) is calculated using the mas...

question_answer

Q: a.) Write down for yourself the secular determinant for the hypothetical molecule linear H3 making t...

A: Hello. Since you have posted multiple questions and not specified which question needs to be solved,...

question_answer

Q: Leaded gasoline contains an additive to prevent engine knocking. On analysis, the additive compound ...

A: Given,51.36 g sample produced 55.90 g of CO2 and 28.61 g of H2OMolar mass of carbon = 12.0107Molar m...

question_answer

Q: What is the general formula for a noncyclic alkane? C?H a. b. If a noncyclic alkane contains 15 carb...

A: The general formula for noncyclic alkane is

question_answer

Q: In a study of the formation of NOx air pollution, a chamber heated to 2200°C was filled with air (0....

A: Given,Initial pressure of N2 = 0.790 atmInitial pressure of O2 = 0.210 atmKp = 0.0530

question_answer

Q: What mass of HClO4 should be present in 0.400 L of solution to obtain a solution with each pH value?...

A: The pH of a given solution can be defined as the molar concentration of the hydrogen ions which are ...

question_answer

Q: A 1.200 g sample of ZnCO3 (s) dissolved in 40.0 mL of a dilute HCl solution (density = 1.10 g/mL) in...

A: The reactants are zinc carbonate and dilute hydrochloric acid.

question_answer

Q: a.) Give the bond order of Li2 ,Be2 ,C2  b.) Give the ground state electron configurations ofCO,NO ,...

A: (a)The bond orders are given as

question_answer

Q: why cyanide is more poisonous than thiocyanate?

A: Cyanide is a very strong ligand. It reacts with Irion in the Haemoglobin in our blood and forms a st...