A 50-mm diameter cylinder is made of a brass for which the stress-strain diagram is as shown. The angle of twist is 5° in a length L = 725 mm. The three points on the nonlinear stress-strain diagram used are (0, 0), (0.0015, 55 MPa), and (0.003, 80 MPa). By fitting the polynomial T = A + By + Cy2 through these points, the following approximate relation has been obtained. T= 46.7 x 10y-6.67 × 10122 Determine the magnitude Tof torque applied to the shaft using this relation and the two equations given below. Pº Y = Ty 2π] ρ?τὰρ 7 (MPa) 100 80 ✓ 60 40 20 0.001 0.002 0.003 Y 0 d = 50 mm k The magnitude T of torque applied to the shaft is kN-m. OF

Mechanics of Materials (MindTap Course List)
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Chapter3: Torsion
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A 50-mm diameter cylinder is made of a brass for which the stress-strain diagram is as shown. The angle of twist is 5° in a length L =
725 mm. The three points on the nonlinear stress-strain diagram used are (0, 0), (0.0015, 55 MPa), and (0.003, 80 MPa). By fitting the
polynomial T = A + By + Cy² through these points, the following approximate relation has been obtained.
T= 46.7 × 10%y-6.67 × 1012/2
Determine the magnitude Tof torque applied to the shaft using this relation and the two equations given below.
Y
Ty
-
ρφ
T (MPa)
2π ζ ρ?τὰρ
100
80
60
40
20
0
0.001 0.002 0.003 Y
d = 50 mm
L
The magnitude T of torque applied to the shaft is
kN.m.
Transcribed Image Text:A 50-mm diameter cylinder is made of a brass for which the stress-strain diagram is as shown. The angle of twist is 5° in a length L = 725 mm. The three points on the nonlinear stress-strain diagram used are (0, 0), (0.0015, 55 MPa), and (0.003, 80 MPa). By fitting the polynomial T = A + By + Cy² through these points, the following approximate relation has been obtained. T= 46.7 × 10%y-6.67 × 1012/2 Determine the magnitude Tof torque applied to the shaft using this relation and the two equations given below. Y Ty - ρφ T (MPa) 2π ζ ρ?τὰρ 100 80 60 40 20 0 0.001 0.002 0.003 Y d = 50 mm L The magnitude T of torque applied to the shaft is kN.m.
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