Answered: A 56.25 kg crate slides down a 36.87°…

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter7: Conservation Of Energy

Section: Chapter Questions

Problem 5P: A block of mass 0.250 kg is placed on top of a light, vertical spring of force constant 5 000 N/m...

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(1.) A 56.25 kg crate slides down a 36.87° slope (inclined plane) that is 32.00 m in length and has a kinetic friction coefficient of 0.3625. The crate is given a downward speed of only 7.500 m/s as it starts down from the top of the slope. Applying the principle of the conservation of mechanical energy in the presence of dissipative forces, determine its final speed as it reaches the bottom of the slope.

Expert Solution

Step 1

Given,

$m a s s o f t h e c r a t e, m = 56.25 k g a n g l e o f i n c l i n a t i o n, θ = 36.87 ° l e n g t h, l = 32.00 m c o e f f i c i e n t o f k i n e t i c, μ = 0.3625 i n i t i a l s p e e d o f t h e c r a t e, u = 7.50 \frac{m}{s}$

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