Can I see a random example of how you could set eq 6.4 and 6.5 equal to each other to find an expected speed. Thank you OCXmat Tools Add-ons HelpLast edit was 8 minutes agoormal textBIUATimes New.11三I | II5In this experiment, an object will be swung in a horizontal circle (see figure l). The force of gravityon the object will be ignored, so the only important force acting on the object on the end of thestring is the tension in the string, which is equal to the weight of the mass(es) hung from the bottomof the string. Note that the mass of the circling object is m and the mass of the hanging object is M.The net force on the circling object is then:F = Mg(Eq. 6.4)Knowing the necessary acceleration to keep an object on a circular path, we can calculate the forcerequired, using Newton's Second Law and (Eq. 6.1):F = mv(Eq. 6.5)By using (Eq. 6.4) and (Eq. 6.5), we can investigate how Newton's Second Law applies to objectsin uniform circular motion.EQUIPMENTFishing Line (120 cm)Washers (15)A Helpful Friend (optional, butuseful)*Tape or Permanent Marker*Spring ScalesII

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Can I see a random example of how you could set eq 6.4 and 6.5 equal to each other to find an expected speed. Thank you

Inquiry into Physics

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Chapter1: The Study Of Motion

Section: Chapter Questions

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Can I see a random example of how you could set eq 6.4 and 6.5 equal to each other to find an expected speed. Thank you

OCX
mat Tools Add-ons Help
Last edit was 8 minutes ago
ormal text
BIUA
Times New.
11
三
I | II5
In this experiment, an object will be swung in a horizontal circle (see figure l). The force of gravity
on the object will be ignored, so the only important force acting on the object on the end of the
string is the tension in the string, which is equal to the weight of the mass(es) hung from the bottom
of the string. Note that the mass of the circling object is m and the mass of the hanging object is M.
The net force on the circling object is then:
F = Mg
(Eq. 6.4)
Knowing the necessary acceleration to keep an object on a circular path, we can calculate the force
required, using Newton's Second Law and (Eq. 6.1):
F = mv
(Eq. 6.5)
By using (Eq. 6.4) and (Eq. 6.5), we can investigate how Newton's Second Law applies to objects
in uniform circular motion.
EQUIPMENT
Fishing Line (120 cm)
Washers (15)
A Helpful Friend (optional, but
useful)*
Tape or Permanent Marker*
Spring Scales
II

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