Question
Asked Dec 9, 2019
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A 6.00g sample of Iodine-131 decays until there is only 0.75g of Iodine-131 remaining. How much time has passsed if Iodine-131 has a half life of 8.0197 days? 

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Expert Answer

Step 1

Given data:

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Initial amount of Iodine-131(N,) = 6.00 g Remaning amount of Iodine-131(N,)=0.75 g 31/1% half-life of Iodine-131 t,,=8.0197 days

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Step 2

The time passed for decay of Iodine-131 from 6.00 g to 0.75 g is calculated by the formula shown below.

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-(1) N, No Where, N is the initial amount. N, is the final amount. t is the total time. is half-life. ty ||

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Step 3

Substitute the given data...

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N, 1 'y 18.0197 days 0.75 g 6.00 g 0.125 = (0.5)8.0197 days (taking log) log (0.125) = log (0.5)8.0197 days log (0.125) = - log (0.5) 8.0197 days (-0.301) -0.903 = 8.0197 days -0.903 8.0197 days -0.301 0.903 x 8.0197 days 0.301 = 3x 8.0197 days = 24.06 days

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Chemistry

Inorganic Chemistry

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