Business
Engineering
Math
Science
Social ScienceA 60kg sled is pulled by a string with a force of 100N and the string makes an angle of 60 degrees above the horizontal (up and to the right). The sled starts at rest and is moving at 2.5 m/s to the right after 5 seconds.1. Find the acceleration of the sled.1. Find the horizontal component of the pull force (Horizontal tension).2. Using the acceleration found in part 1 and the force in part 2, find the force of friction opposing the forward motion.
A 60kg sled is pulled by a string with a force of 100N and the string makes an angle of 60 degrees above the horizontal (up and to the right). The sled starts at rest and is moving at 2.5 m/s to the right after 5 seconds.
1. Find the acceleration of the sled.
1. Find the horizontal component of the pull force (Horizontal tension).
2. Using the acceleration found in part 1 and the force in part 2, find the force of friction opposing the forward motion.
Expert Answer
Given:
Mass of the sled = 60 kg
Force pulling the sled = 100 N at 60 degrees above horizontal
Velocity of sled after 5 seconds = 2.5 m/s
(a) Calculating the acceleration of the sled:
Image Transcriptionclose
Initial velocity of the sled = 0 m/a Final velocity of the sled after 5 seconds 2.5 m/s Total time taken = 5 s Acceleration, a (2.5m/s)-Om/s = 0.5m /s2 5s a 0.5m/s
(b) Calculating the horizo...
Image Transcriptionclose
Fsine F 100N a Fcose fr mg From the FBD of the sled, Horizontal component of the applied force = F cos 0 Substituting the values of F and angle, Horizontal applied force, F =(100N)(cos 60) 50N
Science
Physics
Related Physics Q&A
Find answers to questions asked by student like you
Show more Q&A addQ: In the winter activity of tubing, riders slide down snow covered slopes while sitting on large infla...
A: The change in gravitational potential energy is,Substitute the values,
Q: Concave mirror Experiment object height = 0.60m object distance = 3.00cm Radius of curvature = 4.0...
A: The relation between image distance, object distance and magnification (m) is:
Q: A P8.11 SL: dir Find the x and y coordinates of the center of gravity of a 4.00 ft by 8.00 ft unifor...
A: consider the two rectangles, the big rectangle have area of 16 square feet ( 4.00 ft *4.00 ft) and t...
Q: You have a sample an unknown solid You are tasked with determining the specific heat andlatent of th...
A: In the first experiment, heat lost by the water is the heat gained by the solid
Q: 45. Review. Two constant forces act on an object of mass m = QC 5.00 kg moving in the xy plane as sh...
A: part A:
Q: (b) What torque must be applied to this object to give it an angular acceleration of 1.30 rad/s2 if ...
A: Torque is,
Q: After falling from rest from a height of 35 m, a 0.30-kg ball rebounds upward, reaching a height of ...
A: Given:
Q: for orbital velocity, do you always add 6400 km to the altitude of orbit?
A: Orbital velocity is,
Q: A planet similar to the Earth has a radius 4.3 × 106 m and has an acceleration of gravity of 10 m/s ...
A: Click to see the answer
