A 65g Frisbee is thrown from a point 1.20 m above the ground with a speed of 12.00 m/s. When it has reached a height of 2.70 m, its speed is 10.4831 m/s. How much work was done on the Frisbee by its weight? * 12.3 xBlaCon XY LON XB The XA LON XA Des Xe LON XQ PhyCor XHor XO Mai xG finc X+A loncapa2.physics.sc.edu/res/msu/physicslib/msuphysicslib/13_EnergyConservation/msu-prob28.problem#17E Appsa. Amazon.com: Tiny. A Eligibility Requirem.JavaScript ConceptsMail - OWENS, AYD..e SpotifyR regex101: build, tes..Vim Cheat SheetE Reading listBasic overview of M...Ayden Owens v (Student - section: 1)2021 Fall, Phys 211(Wilson)Messages Courses Help LogoutMain MenuContentsGradesCourse Contents » ... » HW 9 » Dart GunTimerNotesEvaluate Feedback Print O InfoThe potential energy stored in the compressed spring of a dart gun, with a spring constant of 66.00 N/m, is 0.600 J. Find by how much is thespring is compressed.1.348×101 mYou are correct.Your receipt no. is 163-4390 0A 0.030 kg dart is fired straight up. Find the vertical distance the dart travels from its position when the spring is compressed to its highestposition.2.039 mPrevious TriesYou are correct.Your receipt no. is 163-8345 0The same dart is now fired horizontally from a height of 1.10 m. The dart remains in contact until the spring reaches its equilibrium position. Findthe horizontal velocity of the dart at that time.6.325 m/sYou are correct.Your receipt no. is 163-8395 0Find the horizontal distance from the equilibrium position at which the dart hits the ground.4.0801mIf you know how long it takes it to fall to the ground, you can calculate how far it goes in the horizontal direction during that time.Previous TriesPrevious TriesSubmit AnswerIncorrect. Tries 5/15 Previous TriesThis discussion is closed.Send Feedback12:35 AMP Type here to searchLON-CAP..DIO VS Al..E Norton 360O Norton 360Netflix51°FENG11/2/2021

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A 65g Frisbee is thrown from a point 1.20 m above the ground with a speed of 12.00 m/s. When it has reached a height of 2.70 m, its speed is 10.4831 m/s. How much work was done on the Frisbee by its weight?

A 65g Frisbee is thrown from a point 1.20 m above the ground with a speed of 12.00 m/s. When it has reached a height of 2.70 m, its speed is 10.4831 m/s. How much work was done on the Frisbee by its weight?

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter7: Work, Energy, And Energy Resources

Section: Chapter Questions

Problem 43PE: (a) Calculate the power per square meter reaching Earth's upper atmosphere from the Sun. (Take the...

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HI, CAN U PLS MAKE A DETAILED SOLUTION FOR THIS PROBLEM THANK YOU
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You just copied the same answer from Chegg but that one is incorrect... so far these are the results i got but i also think they're not correct. 4(a) The power radiated by the tank can be expressed in the following formula: P = εσA(Tin4 – Tout4) Where, ε = 0.76 σ = 5.67 x 10^-8 W/m2K^4 A = 2.8 m^2 T(Tin^4 – Tout^4) = (58 + 273.15 = 331.15 K)^4 – (19 + 273.15 = 292.15 K)^4 = 4740486867.42 K So Pnet= 0.76 * 5.67 × 10^-8 * 2.9 * 4740486867.42 Pnet = 592.4 W or 0.59 kW 4(b) The power lost through the insulating layer can be calculated using the following formula: Ploss = kA Ttan⁡k−Ts / l where Ploss is the power lost through the insulating layer, k is the thermal conductivity of the rock mineral wool, A is the surface area of the tank, Ttan⁡k is the temperature of the tank, Ts is the temperature of the surroundings, and l is the thickness of the insulating layer. k = 0.032 A = 2.9 m^2 Ttan⁡k = 58 °C Ts = 19°C l= 0.115 m Ploss = 0.032 * 2.9 * 58−19/115 Ploss = 31.47 W…
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