A 7.08 g sample of an ionic compound XCI2 is dissolved in 383 grams of a solvent. The freezing point of the solution is 1.22°C below that of pure solvent. What is the molar mass of this compound? Kf for solvent 4.36°C/m. Use 3 significant figures in this problem. Do not include the units in your answer.

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Chapter11: Properties Of Solutions
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A 7.08 g sample of an ionic compound XCI2 is dissolved in 383 grams of a
solvent. The freezing point of the solution is 1.22°C below that of pure
solvent. What is the molar mass of this compound? Kf for solvent =
4.36°C/m.
Use 3 significant figures in this problem. Do not include the units in your
answer.
Transcribed Image Text:A 7.08 g sample of an ionic compound XCI2 is dissolved in 383 grams of a solvent. The freezing point of the solution is 1.22°C below that of pure solvent. What is the molar mass of this compound? Kf for solvent = 4.36°C/m. Use 3 significant figures in this problem. Do not include the units in your answer.
Expert Solution
Step 1

The molecular weight of the solute can be calculated by using the colligative properties, depression in freezing point. The depression in the freezing point of a solution is given by:

∆Tf = i Kf m

∆T= 1.22oC

i = van't Hoff factor = 3 (for ionic XCl2)

Where m is = molality of the solution =?

Kf is = molal depression constant = 4.36oC/m

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