Calculate the boiling and freezing points of 0.102 mol/kg aqueous solutions of NaCl and of CaCl2. Kb(H2O) = 0.520 °C/(mol/kg) Kf(H2O) = -1.86 °C/(mol/kg) Tb(NaCl) solution: °C Tb(CaCl2) solution: °C Tf(NaCl) solution: °C Tf(CaCl2) solution: °C

Calculate the boiling and freezing points of 0.102 mol/kg aqueous solutions of NaCl and of CaCl2. Kb(H2O) = 0.520 °C/(mol/kg) Kf(H2O) = -1.86 °C/(mol/kg) Tb(NaCl) solution: °C Tb(CaCl2) solution: °C Tf(NaCl) solution: °C Tf(CaCl2) solution: °C

Introductory Chemistry For Today

8th Edition

ISBN:9781285644561

Author:Seager

Publisher:Seager

Chapter7: Solutions And Colloids

Section: Chapter Questions

Problem 7.66E

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Concept explainers

Solutions

Solutions can be considered as homogeneous mixtures which contain two or more than two chemical substances. The chemical substance which is the greater part is defined as solvent. And the chemical substance that is dissolved in a solvent is referred to as solute. Solution chemistry plays an important role in chemistry since it supports many commercial applications of solutions.

Question

Calculate the boiling and freezing points of 0.102 mol/kg aqueous solutions of NaCl and of CaCl₂.

K_b(H₂O) = 0.520 °C/(mol/kg)
K_f(H₂O) = -1.86 °C/(mol/kg)

T_b(NaCl) solution: °C

T_b(CaCl₂) solution: °C

T_f(NaCl) solution: °C

T_f(CaCl₂) solution: °C

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