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A 77.0-mL sample of a 0.203 M potassium sulfate solution is mixed with 55.0 mL of a 0.226 M lead(II) nitrate solution and this reaction occurs:                  K2SO4(aq) + Pb(NO3)2 (aq)    ⟶ 2 KNO3(aq) + PbSO4(s) The solid PbSO4 is collected, dried, and found to have a mass of 2.62 g.  Determine the percent yield.   1 mole PbSO4 = 303.26 g Group of answer choices A.) 69.5% B.) 120% C.) 91.1% D.) 80.1%

A 77.0-mL sample of a 0.203 M potassium sulfate solution is mixed with 55.0 mL of a 0.226 M lead(II) nitrate solution and this reaction occurs:                  K2SO4(aq) + Pb(NO3)2 (aq)    ⟶ 2 KNO3(aq) + PbSO4(s) The solid PbSO4 is collected, dried, and found to have a mass of 2.62 g.  Determine the percent yield.   1 mole PbSO4 = 303.26 g Group of answer choices A.) 69.5% B.) 120% C.) 91.1% D.) 80.1%

General Chemistry - Standalone book (MindTap Course List)
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter4: Chemical Reactions
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Problem 4.159QP: Determine the volume of sulfuric acid solution needed to prepare 37.4 g of aluminum sulfate,...
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A 77.0-mL sample of a 0.203 M potassium sulfate solution is mixed with 55.0 mL of a 0.226 M lead(II) nitrate solution and this reaction occurs:

                 K2SO4(aq) + Pb(NO3)2 (aq)    ⟶ 2 KNO3(aq) + PbSO4(s)

The solid PbSO4 is collected, dried, and found to have a mass of 2.62 g.  Determine the percent yield.   1 mole PbSO4 = 303.26 g

Group of answer choices

A.) 69.5%

B.) 120%

C.) 91.1%

D.) 80.1%

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