A 9.41-g piece of platinum was heated to 98.6 °C in a boiling water bath and then dropped onto ice. When the metal’s temperature had dropped to 0.0 °C, it was found that 0.36 g of ice had melted. What is the specific heat capacity of platinum?
A 9.41-g piece of platinum was heated to 98.6 °C in a boiling water bath and then dropped onto ice. When the metal’s temperature had dropped to 0.0 °C, it was found that 0.36 g of ice had melted. What is the specific heat capacity of platinum?
Given information:
Mass of piece of platinum = 9.41 g
Mass of ice = 0.36 g
Boiling temperature = 98.6 ˚C
Taking enthalpy of fusion of water = 334 J/g
As , amount of heat lost by metal is equal to amount of heat gained by metal. Therefore, the energy released and utilized will also be equal.
Thus, the amount of energy/heat produced by 0.37 g of ice is calculated as follows:
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Amount of energy = 0.36 gx334 J/g = 120.24 J
Thus, the specific heat of platinu...
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Amount of heat required (Q)=mxCxAT 120.24 J 9.41 g 98.6 °CxC 120.24 J C = 9.41 gx98.6 °C 0.129 J/g.C
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