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- What is meant by the sample space of an experiment?In a study of cell phone use and brain hemispheric dominance, an Internet survey was e-mailed to 2482 subjects randomly selected from an online group involved with ears. 1095 surveys were returned. Construct a 90% confidence interval for the proportion of returned surveys. a) p = .441 b) E= 0.016 c) Construct the confidence interval= .425< p < .457 ***QUESTION** Write a statement that correctly interprets the confidence interval. Choose the correct answer below. A. 90% of sample proportions will fall between the lower bound and the upper bound. B. There is a 90% chance that the true value of the population proportion will fall between the lower bound and the upper bound. C. One has 90% confidence that the interval from the lower bound to the upper bound actually does contain the true value of the population proportion. D. One has 90% confidence that the sample proportion is equal to the population proportion.Drinking A national health organization, concerned about drinking in middle school students, surveyed 220 randomly selected US 8th-grade students and found that 18 of them had had a drink of alcohol in the past month.(a) Find and interpret a 95% confidence interval for the proportion p of US 8th-grade students who drink alcohol.(b) Give the best estimate for p and give the margin of error for the estimate.
- In a study of the accuracy of fast food drive-through orders, Restaurant A had 307 accurate orders and 64 that were not accurate. a. Construct a 90% confidence interval estimate of the percentage of orders that are not accurate. b. Compare the results from part (a) to this 90% confidence interval for the percentage of orders that are not accurate at Restaurant B: 0.161<p<0.222. What do you conclude?In a study of the accuracy of fast food drive-through orders, Restaurant A had 290 accurate orders and 56 that were not accurate. a. Construct a 90% confidence interval estimate of the percentage of orders that are not accurate. b. Compare the results from part (a) to this 90% confidence interval for the percentage of orders that are not accurate at Restaurant B: 0.146 <p < 0.212. What do you conclude?Question 2 - (Please answer both a and b) A recent survey showed that from a sample of 500 packages delivered by a Postal Service, 480 were delivered on time. a) Construct a 95% confidence interval for the proportion of all packages that are delivered on time by the Postal Service. b) The manager of the Postal Services claims that 98 percent of their mail are delivered on time. Test at the 1% significance level to determine whether the true proportion is less than 98 percent.
- A research group studying cell phone habits asked the question “Do you ever use your cell phone to make a payment at a convenience store?” to people selected from two random samples of cell phone users. One sample consisted of older adults, ages 35 years and older, and the other sample consisted of younger adults, ages 18 years to 34 years. The proportion of people who answered yes in each sample was used to create a 95 percent confidence interval of (0.097,0.125)(0.097,0.125) to estimate the difference (younger minus older) between the population proportions of people who would answer yes to the question. Which of the following is the best description of what is meant by 95 percent confidence? In repeated random sampling with the same sample size, approximately 95% of the sample proportions from the younger group will be between 0.097 and 0.125 greater than the sample proportion from the older group. A In repeated random sampling with the same sample size,…Reseacrch commissioned by AT&T and conducted by Braun Research in 2015 polled 2,067 people in the U.S. aged 16-65 who use their smartphone and drive at least once a day. When asked if they used Facebook while driving, 558 respondents answered "yes". a. What is the point estimate for the proportion of drives who access Facebook while driving? b. What is the margin of error for a 95% confidence interval? c. Construct a confidence interval for proportion of all drivers who take pictures while driving. d. Interpret the interval. e. An independent researcher claims that 30% of drivers use Facebook behind the wheel. Based on the interval, is the claim valid? Explain.1. A recent Gallop poll showed that 672 of 1019 adults nationwide think that marijuana should be legalized. a) Find the margin of error that corresponds to a 95% confidence interval. b) Find the 95% confidence interval estimate of the proportion of adults nationwide who think marijuana should be legalized
- Gender and Gun Control A survey reported in Time magazine included the question “Do you favor a federal law requiring a 15 day waiting period to purchase a gun?” Results from a random sample of US citizens showed that 318 of the 520 men who were surveyed supported this proposed law while 379 of the 460 women sampled said “yes”. Use this information to find and interpret a 90% confidence interval for the difference in the proportions of men and women who agree with this proposed law.The drug Viagra became available in the U.S. in May 1988, in the wake of an advertising campaign that was unprecedented in scope and intensity. A Gallup poll found that by the end of the first week of May, 643 out of 1,005 adults were aware that Viagra was an impotency medication. A)Suppose researchers calculated a 90% confidence interval to be (0.60, 0.68). What is the correct interpretation of this interval? -We are 90% confident that the true sample proportion of adults that were aware of Viagra after one week lies between 0.60 and 0.68. -We are 90% confident that the true proportion of adults that were aware of Viagra after one week lies between 0.60 and 0.68. -90% of adults fall between 0.60 and 0.68. -The is a 90% probability that the true proportion of adults that were aware of Viagra after one week lies between 0.60 and 0.68. b)Suppose the researchers decided to take a sample of 500 rather than 1005, how would this change the margin of error? The margin of error…In a study of the accuracy of fast food drive-through orders, Restaurant A had 298accurate orders and 51 that were not accurate. a. Construct a 90% confidence interval estimate of the percentage of orders that are not accurate. b. Compare the results from part (a) to this 90% confidence interval for the percentage of orders that are not accurate at Restaurant B: 0.127<p<0.191. What do you conclude? a. Construct a 90% confidence interval. Express the percentages in decimal form. ___<p<___ (Round to three decimal places as needed.) (This is used directly in response to B).