(a) A common- emitter amplifier is shown in Fig. 3(a) where,1,= 2 kll, ro = ∞, ß = 99, RE = 1kn, VRE (on) = 0.7 V and VCEO = 8 V. Assume that Vr = 26 mV. (i) Draw the small-signal equivalent circuit (ii) Design the amplifier circuit for input R = 18 kN. (iii) Determine the voltage gain, Aps = vo/vs %3D Vcc = 15 V R RC Cc2 Rs = Cci 5 kN 0a + o ww R = 2 kn VBE RB 1 kn VEE = -15 V ww

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(a) A common- emitter amplifier is shown in Fig. 3(a), where, r= 2 kN, ro = co, ß = 99,
RE = 1kn, VBE (0n) = 0.7 V and VceQ = 8 V. Assume that Vr = 26 mV.
(i) Draw the small-signal equivalent circuit
(ii) Design the amplifier circuit for input R; = 18 kN.
(iii) Determine the voltage gain, Aps = vo/vs
Vcc= 15 V
RC
Cc2
Rs =
Cci
5 kN
Oa + 어
ww
R1 =
2 kN
VBE
RB
R=
1 kN
VEE =
- 15 V
Fig. 3(a)
Transcribed Image Text:(a) A common- emitter amplifier is shown in Fig. 3(a), where, r= 2 kN, ro = co, ß = 99, RE = 1kn, VBE (0n) = 0.7 V and VceQ = 8 V. Assume that Vr = 26 mV. (i) Draw the small-signal equivalent circuit (ii) Design the amplifier circuit for input R; = 18 kN. (iii) Determine the voltage gain, Aps = vo/vs Vcc= 15 V RC Cc2 Rs = Cci 5 kN Oa + 어 ww R1 = 2 kN VBE RB R= 1 kN VEE = - 15 V Fig. 3(a)
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