a) A house walls that are 19 cm thick and have an average thermal conductivity twice that of glass wool. Assume there are no windows or doors. The walls' surface area is 1150000 cm2 and their inside surface is at 19°C, while their outside surface is at 5°C. (Thermal conductivity of glass wool is 0.042 W/m°C) (i) Calculate the rate of heat conduction through house walls? (ii) How many 100W room heaters would be needed to balance the heat transfer due to conduction? (approximate number)

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Chapter1: Temperature And Heat
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a) A house walls that are 19 cm thick and have an
average thermal conductivity twice that of glass
wool. Assume there are no windows or doors.
The walls' surface area is 1150000 cm? and their
inside surface is at 19°C, while their outside
surface is at 5°C. (Thermal conductivity of glass
wool is 0.042 W/m°C)
(i) Calculate the rate of heat conduction
through house walls?
(ii) How many 100W room heaters would be
needed to balance the heat transfer due to
conduction? (approximate number)
Transcribed Image Text:a) A house walls that are 19 cm thick and have an average thermal conductivity twice that of glass wool. Assume there are no windows or doors. The walls' surface area is 1150000 cm? and their inside surface is at 19°C, while their outside surface is at 5°C. (Thermal conductivity of glass wool is 0.042 W/m°C) (i) Calculate the rate of heat conduction through house walls? (ii) How many 100W room heaters would be needed to balance the heat transfer due to conduction? (approximate number)
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